AP®︎ Precalculus: Unit 4 Practice Test

Prepare for your quiz, test, or the AP exam with focused practice questions on Unit 4 of AP Precalculus – Functions Involving Parameters, Vectors, and Matrices.


Questions List

Unit 4 (All Topics)

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Question 1 Topic 4.1Easy

A parametric function is given by x(t)=t2−3tx(t)=t^2-3t and y(t)=2t+1y(t)=2t+1.

Which point is produced when t=−1t=-1?

A(−1,4)(-1,4)
B(4,−1)(4,-1)
C(−2,−1)(-2,-1)
D(2,−1)(2,-1)

What You’re Being Tested On:

Explore the learning objectives taken directly from the College Board’s AP® Precalculus Curriculum. Ensure you’re prepared for the exact topics covered on the AP® exam, in-class tests, and quizzes, and gain confidence in your mastery of the material.

Unit 4: Functions Involving Parameters, Vectors, and Matrices

This unit introduces parametric functions, vectors, and matrices as tools for representing motion, transformations, and relationships between multiple quantities.

Topic 4.1: Parametric Functions

Learning Objective: 4.1.A

Construct a graph or table of values for a parametric function represented analytically.

Essential Knowledge: 4.1.A.1

A parametric function in R2\mathbb{R}^{2}, the set of all ordered pairs of two real numbers, consists of a set of two parametric equations in which two dependent variables, xx and yy, are dependent on a single independent variable, tt, called the parameter.

Essential Knowledge: 4.1.A.2

Because variables xx and yy are dependent on the independent variable, tt, the coordinates (xi,yi)(x_i, y_i) at time tit_i can be written as functions of tt and can be expressed as the single parametric function f(t)=(x(t),y(t))f(t) = (x(t), y(t)), where in this case xx and yy are names of two functions.

Essential Knowledge: 4.1.A.3

A numerical table of values can be generated for the parametric function f(t)=(x(t),y(t))f(t) = (x(t), y(t)) by evaluating xix_i and yiy_i at several values of tit_i within the domain.

Essential Knowledge: 4.1.A.4

A graph of a parametric function can be sketched by connecting several points from the numerical table of values in order of increasing value of tt.

Essential Knowledge: 4.1.A.5

The domain of the parametric function ff is often restricted, which results in start and end points on the graph of ff.

Topic 4.2: Parametric Functions Modeling Planar Motion

Learning Objective: 4.2.A

Identify key characteristics of a parametric planar motion function that are related to position.

Essential Knowledge: 4.2.A.1

A parametric function given by f(t)=(x(t),y(t))f(t) = (x(t), y(t)) can be used to model particle motion in the plane. The graph of this function indicates the position of a particle at time tt.

Essential Knowledge: 4.2.A.2

The horizontal and vertical extrema of a particle’s motion can be determined by identifying the maximum and minimum values of the functions x(t)x(t) and y(t)y(t), respectively.

Essential Knowledge: 4.2.A.3

The real zeros of the function x(t)x(t) correspond to yy-intercepts, and the real zeros of y(t)y(t) correspond to xx-intercepts.

Topic 4.3: Parametric Functions and Rates of Change

Learning Objective: 4.3.A

Identify key characteristics of a parametric planar motion function that are related to direction and rate of change.

Essential Knowledge: 4.3.A.1

As the parameter increases, the direction of planar motion of a particle can be analyzed in terms of xx and yy independently. If x(t)x(t) is increasing or decreasing, the direction of motion is to the right or left, respectively. If y(t)y(t) is increasing or decreasing, the direction of motion is up or down, respectively.

Essential Knowledge: 4.3.A.2

At any given point in the plane, the direction of planar motion may be different for different values of tt.

Essential Knowledge: 4.3.A.3

The same curve in the plane can be parametrized in different ways and can be traversed in different directions with different parametric functions.

Essential Knowledge: 4.3.A.4

Over a given interval [t1,t2][t_1, t_2] within the domain, the average rate of change can be computed for x(t)x(t) and y(t)y(t) independently. The ratio of the average rate of change of yy to the average rate of change of xx gives the slope of the graph between the points on the curve corresponding to t1t_1 and t2t_2, so long as the average rate of change of x(t)≠0x(t) \ne 0.

Topic 4.4: Parametrically Defined Circles and Lines

Learning Objective: 4.4.A

Express motion around a circle or along a line segment parametrically.

Essential Knowledge: 4.4.A.1

A complete counterclockwise revolution around the unit circle that starts and ends at (1,0)(1, 0) and is centered at the origin can be modeled by (x(t),y(t))=(cos⁡t,sin⁡t)(x(t), y(t)) = (\cos t, \sin t) with domain 0≤t≤2π0 \leq t \leq 2\pi.

Essential Knowledge: 4.4.A.2

Transformations of the parametric function (x(t),y(t))=(cos⁡t,sin⁡t)(x(t), y(t)) = (\cos t, \sin t) can model any circular path traversed in the plane.

Essential Knowledge: 4.4.A.3

A linear path along the line segment from the point (x1,y1)(x_1, y_1) to the point (x2,y2)(x_2, y_2) can be parametrized many ways, including using an initial position (x1,y1)(x_1, y_1) and rates of change for xx with respect to tt and yy with respect to tt.

Topic 4.5: Implicitly Defined Functions

Learning Objective: 4.5.A

Construct a graph of an equation involving two variables.

Essential Knowledge: 4.5.A.1

An equation involving two variables can implicitly describe one or more functions.

Essential Knowledge: 4.5.A.2

An equation involving two variables can be graphed by finding solutions to the equation.

Essential Knowledge: 4.5.A.3

Solving for one of the variables in an equation involving two variables can define a function whose graph is part or all of the graph of the equation.

Learning Objective: 4.5.B

Determine how the two quantities related in an implicitly defined function vary together.

Essential Knowledge: 4.5.B.1

For ordered pairs on the graph of an implicitly defined function that are close together, if the ratio of the change in the two variables is positive, then the two variables simultaneously increase or both decrease; conversely, if the ratio is negative, then as one variable increases, the other decreases.

Essential Knowledge: 4.5.B.2

The rate of change of xx with respect to yy or of yy with respect to xx can be zero, indicating vertical or horizontal intervals, respectively.

Topic 4.6: Conic Sections

Learning Objective: 4.6.A

Represent conic sections with horizontal or vertical symmetry analytically.

Essential Knowledge: 4.6.A.1

A parabola with vertex (h,k)(h, k) can, if a≠0a \ne 0, be represented analytically as x−h=a(y−k)2x - h = a(y - k)^2 if it opens left or right, or as y−k=a(x−h)2y - k = a(x - h)^2 if it opens up or down.

Essential Knowledge: 4.6.A.2

An ellipse centered at (h,k)(h, k) with horizontal radius aa and vertical radius bb can be represented analytically as (x−h)2a2+(y−k)2b2=1\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1. A circle is a special case of an ellipse where a=ba = b.

Essential Knowledge: 4.6.A.3

A hyperbola centered at (h,k)(h, k) with vertical and horizonal lines of symmetry can be represented algebraically as (x−h)2a2−(y−k)2b2=1\frac{(x - h)^2}{a^2} - \frac{(y - k)^2}{b^2} = 1 for a hyperbola opening left and right, or as (y−k)2b2−(x−h)2a2=1\frac{(y - k)^2}{b^2} - \frac{(x - h)^2}{a^2} = 1 for a hyperbola opening up and down. The asymptotes are y−k=±ba(x−h)y - k = \pm \frac{b}{a}(x - h).

Topic 4.7: Parametrization of Implicitly Defined Functions

Learning Objective: 4.7.A

Represent a curve in the plane parametrically.

Essential Knowledge: 4.7.A.1

A parametrization (x(t),y(t))(x(t), y(t)) for an implicitly defined function will, when x(t)x(t) and y(t)y(t) are substituted for xx and yy, respectively, satisfy the corresponding equation for every value of tt in the domain.

Essential Knowledge: 4.7.A.2

If ff is a function of xx, then y=f(x)y = f(x) can be parametrized as (x(t),y(t))=(t,f(t))(x(t), y(t)) = (t, f(t)). If ff is invertible, its inverse can be parametrized as (x(t),y(t))=(f(t),t)(x(t), y(t)) = (f(t), t) for an appropriate interval of tt.

Learning Objective: 4.7.B

Represent conic sections parametrically.

Essential Knowledge: 4.7.B.1

A parabola can be parametrized in the same way that any equation that can be solved for xx or yy can be parametrized. Equations that can be solved for xx can be parametrized as (x(t),y(t))=(f(t),t)(x(t), y(t)) = (f(t), t) by solving for xx and replacing yy with tt. Equations that can be solved for yy can be parametrized as (x(t),y(t))=(t,f(t))(x(t), y(t)) = (t, f(t)) by solving for yy and replacing xx with tt.

Essential Knowledge: 4.7.B.2

An ellipse can be parametrized using the trigonometric functions x(t)=h+acos⁡tx(t) = h + a\cos t and y(t)=k+bsin⁡ty(t) = k + b\sin t for 0≤t≤2π0 \le t \le 2\pi.

Essential Knowledge: 4.7.B.3

A hyperbola can be parametrized using trigonometric functions. For a hyperbola that opens left and right, the functions are x(t)=h+asec⁡tx(t) = h + a\sec t and y(t)=k+btan⁡ty(t) = k + b\tan t for 0≤t≤2π0 \le t \le 2\pi. For a hyperbola that opens up and down, the functions are x(t)=h+atan⁡tx(t) = h + a\tan t and y(t)=k+bsec⁡ty(t) = k + b\sec t for 0≤t≤2π0 \le t \le 2\pi.

Topic 4.8: Vectors

Learning Objective: 4.8.A

Identify characteristics of a vector.

Essential Knowledge: 4.8.A.1

A vector is a directed line segment. When a vector is placed in the plane, the point at the beginning of the line segment is called the tail, and the point at the end of the line segment is called the head. The length of the line segment is the magnitude of the vector.

Essential Knowledge: 4.8.A.2

A vector P1P2→\overrightarrow{P_1P_2} with two components can be plotted in the xyxy-plane from P1=(x1,y1)P_1=(x_1,y_1) to P2=(x2,y2)P_2=(x_2,y_2). The vector is identified by aa and bb, where a=x2−x1a=x_2-x_1 and b=y2−y1b=y_2-y_1. The vector can be expressed as ⟨a,b⟩\langle a,b\rangle. A zero vector ⟨0,0⟩\langle 0,0\rangle is the trivial case when P1=P2P_1=P_2.

Essential Knowledge: 4.8.A.3

The direction of the vector is parallel to the line segment from the origin to the point with coordinates (a,b)(a,b). The magnitude of the vector is the square root of the sum of the squares of the components.

Essential Knowledge: 4.8.A.4

For a vector represented geometrically in the plane, the components of the vector can be found using trigonometry.

Learning Objective: 4.8.B

Determine sums and products involving vectors.

Essential Knowledge: 4.8.B.1

The multiplication of a constant and a vector results in a new vector whose components are found by multiplying the constant by each of the components of the original vector. The new vector is parallel to the original vector.

Essential Knowledge: 4.8.B.2

The sum of two vectors in R2\mathbb{R}^2 is a new vector whose components are found by adding the corresponding components of the original vectors. The new vector can be represented graphically as a vector whose tail corresponds to the tail of the first vector and whose head corresponds to the head of the second vector when the second vector’s tail is located at the first vector’s head.

Essential Knowledge: 4.8.B.3

The dot product of two vectors is the sum of the products of their corresponding components. That is, ⟨a1,b1⟩⋅⟨a2,b2⟩=a1a2+b1b2\langle a_1,b_1\rangle\cdot\langle a_2,b_2\rangle=a_1a_2+b_1b_2.

Learning Objective: 4.8.C

Determine a unit vector for a given vector.

Essential Knowledge: 4.8.C.1

A unit vector is a vector of magnitude 1. A unit vector in the same direction as a given nonzero vector can be found by scalar multiplying the vector by the reciprocal of its magnitude.

Essential Knowledge: 4.8.C.2

The vector ⟨a,b⟩\langle a,b\rangle can be expressed as ai⃗+bj⃗a\vec{i}+b\vec{j} in R2\mathbb{R}^2, where i⃗\vec{i} and j⃗\vec{j} are unit vectors in the xx and yy directions, respectively. That is, i⃗=⟨1,0⟩\vec{i}=\langle 1,0\rangle and j⃗=⟨0,1⟩\vec{j}=\langle 0,1\rangle.

Learning Objective: 4.8.D

Determine angle measures between vectors and magnitudes of vectors involved in vector addition.

Essential Knowledge: 4.8.D.1

The dot product is geometrically equivalent to the product of the magnitudes of the two vectors and the cosine of the angle between them. Therefore, if the dot product of two nonzero vectors is zero, then the vectors are perpendicular.

Essential Knowledge: 4.8.D.2

The Law of Sines and Law of Cosines can be used to determine side lengths and angle measures of triangles formed by vector addition.

Topic 4.9: Vector-Valued Functions

Learning Objective: 4.9.A

Represent planar motion in terms of vector-valued functions.

Essential Knowledge: 4.9.A.1

The position of a particle moving in a plane that is given by the parametric function f(t)=(x(t),y(t))f(t) = (x(t), y(t)) may be expressed as a vector-valued function, p(t)=x(t)i⃗+y(t)j⃗p(t) = x(t)\vec{i} + y(t)\vec{j} or p(t)=⟨x(t),y(t)⟩p(t) = \langle x(t), y(t)\rangle. The magnitude of the position vector at time tt gives the distance of the particle from the origin.

Essential Knowledge: 4.9.A.2

The vector-valued function v(t)=⟨x(t),y(t)⟩v(t) = \langle x(t), y(t)\rangle can be used to express the velocity of a particle moving in a plane at different times, tt. At time tt, the sign of x(t)x(t) indicates if the particle is moving right or left, and the sign of y(t)y(t) indicates if the particle is moving up or down. The magnitude of the velocity vector at time tt gives the speed of the particle.

Topic 4.10: Matrices

Learning Objective: 4.10.A

Determine the product of two matrices.

Essential Knowledge: 4.10.A.1

An n×mn \times m matrix is an array consisting of nn rows and mm columns.

Essential Knowledge: 4.10.A.2

Two matrices can be multiplied if the number of columns in the first matrix equals the number of rows in the second matrix. The product of the matrices is a new matrix in which the component in the iith row and jjth column is the dot product of the iith row of the first matrix and the jjth column of the second matrix.

Topic 4.11: The Inverse and Determinant of a Matrix

Learning Objective: 4.11.A

Determine the inverse of a \(2 \times 2\) matrix.

Essential Knowledge: 4.11.A.1

The identity matrix, II, is a square matrix consisting of 1s on the diagonal from the top left to bottom right and 0s everywhere else.

Essential Knowledge: 4.11.A.2

Multiplying a square matrix by its corresponding identity matrix results in the original square matrix.

Essential Knowledge: 4.11.A.3

The product of a square matrix and its inverse, when it exists, is the identity matrix of the same size.

Essential Knowledge: 4.11.A.4

The inverse of a 2×22 \times 2 matrix, when it exists, can be calculated with or without technology.

Learning Objective: 4.11.B

Apply the value of the determinant to invertibility and vectors.

Essential Knowledge: 4.11.B.1

The determinant of the matrix A=[abcd]A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} is ad−bcad - bc. The determinant can be calculated with or without technology and is denoted det⁡(A)\det(A).

Essential Knowledge: 4.11.B.2

If a 2×22 \times 2 matrix consists of two column or row vectors from R2\mathbb{R}^2, then the nonzero absolute value of the determinant of the matrix is the area of the parallelogram spanned by the vectors represented in the columns or rows of the matrix. If the determinant equals 0, then the vectors are parallel.

Essential Knowledge: 4.11.B.3

The square matrix AA has an inverse if and only if det⁡(A)≠0\det(A) \ne 0.

Topic 4.12: Linear Transformations and Matrices

Learning Objective: 4.12.A

Determine the output vectors of a linear transformation using a \(2 \times 2\) matrix.

Essential Knowledge: 4.12.A.1

A linear transformation is a function that maps an input vector to an output vector such that each component of the output vector is the sum of constant multiples of the input vector components.

Essential Knowledge: 4.12.A.2

A linear transformation will map the zero vector to the zero vector.

Essential Knowledge: 4.12.A.3

A single vector in R2\mathbb{R}^{2} can be expressed as a 2×12 \times 1 matrix. A set of nn vectors in R2\mathbb{R}^{2} can be expressed as a 2×n2 \times n matrix.

Essential Knowledge: 4.12.A.4

For a linear transformation, LL, from R2\mathbb{R}^{2} to R2\mathbb{R}^{2}, there is a unique 2×22 \times 2 matrix, AA, such that L(v⃗)=Av⃗L(\vec{v}) = A\vec{v} for vectors in R2\mathbb{R}^{2}. Conversely, for a given 2×22 \times 2 matrix, AA, the function L(v⃗)=Av⃗L(\vec{v}) = A\vec{v} is a linear transformation from R2\mathbb{R}^{2} to R2\mathbb{R}^{2}.

Essential Knowledge: 4.12.A.5

Multiplication of a 2×22 \times 2 transformation matrix, AA, and a 2×n2 \times n matrix of nn input vectors gives a 2×n2 \times n matrix of the nn output vectors for the linear transformation L(v⃗)=Av⃗L(\vec{v}) = A\vec{v}.

Topic 4.13: Matrices as Functions

Learning Objective: 4.13.A

Determine the association between a linear transformation and a matrix.

Essential Knowledge: 4.13.A.1

The linear transformation mapping ⟨x,y⟩\langle x, y\rangle to ⟨a11x+a12y,a21x+a22y⟩\langle a_{11}x + a_{12}y, a_{21}x + a_{22}y\rangle is associated with the matrix [a11a12a21a22]\begin{bmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{bmatrix}.

Essential Knowledge: 4.13.A.2

The mapping of the unit vectors in a linear transformation provides valuable information for determining the associated matrix.

Essential Knowledge: 4.13.A.3

The matrix [cos⁡θ−sin⁡θsin⁡θcos⁡θ]\begin{bmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{bmatrix} is associated with a linear transformation of vectors that rotates every vector an angle θ\theta counterclockwise about the origin.

Essential Knowledge: 4.13.A.4

The absolute value of the determinant of a 2×22 \times 2 transformation matrix gives the magnitude of the dilation of regions in R2\mathbb{R}^2 under the transformation.

Learning Objective: 4.13.B

Determine the composition of two linear transformations.

Essential Knowledge: 4.13.B.1

The composition of two linear transformations is a linear transformation.

Essential Knowledge: 4.13.B.2

The matrix associated with the composition of two linear transformations is the product of the matrices associated with each linear transformation.

Learning Objective: 4.13.C

Determine the inverse of a linear transformation.

Essential Knowledge: 4.13.C.1

Two linear transformations are inverses if their composition maps any vector to itself.

Essential Knowledge: 4.13.C.2

If a linear transformation, LL, is given by L(v⃗)=Av⃗L(\vec{v}) = A\vec{v}, then its inverse transformation is given by L−1(v⃗)=A−1v⃗L^{-1}(\vec{v}) = A^{-1}\vec{v}, where A−1A^{-1} is the inverse of the matrix AA.

Topic 4.14: Matrices Modeling Contexts

Learning Objective: 4.14.A

Construct a model of a scenario involving transitions between two states using matrices.

Essential Knowledge: 4.14.A.1

A contextual scenario can indicate the rate of transitions between states as percent changes. A matrix can be constructed based on these rates to model how states change over discrete intervals.

Learning Objective: 4.14.B

Apply matrix models to predict future and past states for \(n\) transition steps.

Essential Knowledge: 4.14.B.1

The product of a matrix that models transitions between states and a corresponding state vector can predict future states.

Essential Knowledge: 4.14.B.2

Repeated multiplication of a matrix that models the transitions between states and corresponding resultant state vectors can predict the steady state, a distribution between states that does not change from one step to the next.

Essential Knowledge: 4.14.B.3

The product of the inverse of a matrix that models transitions between states and a corresponding state vector can predict past states.