AP®︎ Physics 1: Topic 6.5 Practice Test

Prepare for your quiz, test, or the AP exam with focused practice questions on Topic 6.5 of AP Physics 1 – Rolling.


Questions List

Topic 6.5

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Q2
Q3
Q4
Q5
Q6
Q7
Q8
Q9
Q10
Q11
Q12
Q13
Q14
Q15
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Q17

Question 1 Easy

An object of mass MM and radius RR rolls without slipping. Its center of mass moves at speed vv, and the object rotates with angular speed ω\omega about an axis through its center of mass. Its rotational inertia about that axis is II.

Which of the following expressions gives the object's total kinetic energy?
A12Mv2\frac{1}{2}Mv^2
B12Iω2\frac{1}{2}I\omega^2
C12Mv2+12Iω2\frac{1}{2}Mv^2 + \frac{1}{2}I\omega^2
D12Mv2+12(I+MR2)ω2\frac{1}{2}Mv^2 + \frac{1}{2}(I+MR^2)\omega^2

What You’re Being Tested On:

Explore the learning objectives taken directly from the College Board’s AP® Physics 1 Curriculum. Ensure you’re prepared for the exact topics covered on the AP® exam, in-class tests, and quizzes, and gain confidence in your mastery of the material.

Topic 6.5: Rolling

Boundary Statements official exam scope notes

  • Rolling friction is beyond the scope of AP Physics 1.
  • The precise mathematical relationships between linear and angular quantities while a rigid body is rolling while slipping are beyond the scope of AP Physics 1 and 2, and students will not be expected to model those relationships quantitatively. However, students are expected to qualitatively explain the changes to linear and angular quantities while a rigid body is rolling while slipping.

Learning Objective: 6.5.A

Describe the kinetic energy of a system that has translational and rotational motion.

Essential Knowledge: 6.5.A.1

The total kinetic energy of a system is the sum of the system’s translational and rotational kinetic energies. Relevant equation: Ktot=Ktrans+KrotK_{tot} = K_{trans} + K_{rot}

Learning Objective: 6.5.B

Describe the motion of a system that is rolling without slipping.

Essential Knowledge: 6.5.B.1

While rolling without slipping, the translational motion of a system’s center of mass is related to the rotational motion of the system itself with the equations: Δxcm=rΔθ\Delta x_{cm} = r\Delta\theta; vcm=rωv_{cm} = r\omega; acm=rαa_{cm} = r\alpha

Essential Knowledge: 6.5.B.2

For ideal cases, rolling without slipping implies that the frictional force does not dissipate any energy from the rolling system.

Learning Objective: 6.5.C

Describe the motion of a system that is rolling while slipping.

Essential Knowledge: 6.5.C.1

When slipping, the motion of a system’s center of mass and the system’s rotational motion cannot be directly related.

Essential Knowledge: 6.5.C.2

When a rotating system is slipping relative to another surface, the point of application of the force of kinetic friction exerted on the system moves with respect to the surface, so the force of kinetic friction will dissipate energy from the system.