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Reading Time: 6 min
Last Updated: March 25, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: March 25, 2026
Main Ideas: 5

Topic 5.3 Notes – Torque

Verified for 2027 AP® Physics C: Mechanics Exam
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Just like forces change an object’s linear motion, torques change its rotational motion. Everything here revolves around three ideas: torque depends on where the force is applied, only the perpendicular component matters, and torque is a vector found using a cross product.

1. What Torque Is

If force measures how strongly something translates, torque measures how strongly something rotates about a chosen pivot.

Later you’ll use ∑τ⃗=Iα⃗ \sum \vec{\tau} = I\vec{\alpha} but right now the focus is identifying and describing individual torques.

Vector definition

τ⃗=r⃗×F⃗ \vec{\tau} = \vec{r} \times \vec{F}

  • r⃗\vec{r} is the position vector from the pivot to where the force is applied
  • F⃗\vec{F} is the applied force
  • The pivot must be specified. Change the pivot and the torques change.

Magnitude

∣τ⃗∣=rFsin⁡θ |\vec{\tau}| = rF\sin\theta

  • rr is the distance from pivot to force application point
  • θ\theta is the angle between r⃗\vec{r} and F⃗\vec{F}

Only the perpendicular component of the force contributes.

Special cases:

  • θ=90∘\theta = 90^\circ → maximum torque → τ=rF\tau = rF
  • θ=0∘\theta = 0^\circ or 180∘180^\circ → zero torque

Units are N⋅m\text{N}\cdot\text{m}. Same units as energy, but torque is a vector, not a scalar.

2. Components of the Torque Formula

Position Vector r⃗\vec{r}

This is where students mess up.

  • It always starts at the pivot
  • It ends at the point where the force is applied
  • Direction matters for the cross product

If you draw it backward, your torque direction will be wrong.

Perpendicular Force Component

From rFsin⁡θrF\sin\theta:

τ=rF⊥ \tau = rF_\perp

where F⊥=Fsin⁡θF_\perp = F\sin\theta.

So you can either:

  • Break the force into components and use the perpendicular one, or
  • Use rFsin⁡θrF\sin\theta directly.

Same physics either way.

Lever Arm (Moment Arm)

There’s an equivalent and often easier method.

The lever arm r⊥r_\perp is the perpendicular distance from the pivot to the line of action of the force.

τ=r⊥F \tau = r_\perp F

And since r⊥=rsin⁡θr_\perp = r\sin\theta, this matches the earlier formula.

Here’s what that geometry looks like in a typical setup with an angled force:

Torque geometry: rr, θ\theta, and lever arm r⊥r_\perp

Notice how the dashed perpendicular from the pivot to the dashed line of action gives r⊥r_\perp. That distance alone determines how effective the force is at causing rotation.

Important consequences:

  • A small force far from the pivot can equal a large force close in.
  • If the force acts through the pivot, the lever arm is zero → no torque.
  • If the force is directed straight toward or away from the pivot, r⊥=0r_\perp = 0.

AP problems often hide this in geometry. Always look for that perpendicular distance.

3. Direction of Torque and the Cross Product

Torque direction comes from the cross product.

For any A⃗×B⃗\vec{A} \times \vec{B}:

  • Magnitude is ABsin⁡θAB\sin\theta
  • Direction is perpendicular to the plane containing them

So τ⃗\vec{\tau} is perpendicular to both r⃗\vec{r} and F⃗\vec{F}.

Right-hand rule

The diagram below shows the cross product A⃗×B⃗\vec{A} \times \vec{B} and the hand motion that determines its direction.

Study guide illustration

Right-hand rule for the cross product

How to apply it for torque:

  1. Point fingers along r⃗\vec{r}
  2. Curl toward F⃗\vec{F}
  3. Your thumb gives the direction of τ⃗\vec{\tau}

In 2D:

  • Out of the page → counterclockwise → usually positive
  • Into the page → clockwise → usually negative

On most quizzes and FRQs, torque becomes a signed scalar. You decide a sign convention and stay consistent.

4. Drawing Force Diagrams for Torque Problems

A torque diagram is basically a free-body diagram with locations included.

You must show:

  • The rigid object
  • The pivot point
  • Every force
  • Where each force is applied

If you leave out location, you can’t determine torque.

For each force, ask:

  • Does it pass through the pivot? → zero torque
  • Is it parallel to r⃗\vec{r}? → zero torque
  • Does it try to rotate CW or CCW?

Example thinking:

  • Weight at the end of a horizontal beam about a wall hinge → clockwise.
  • Normal force at the hinge → zero torque about that hinge.

The exam loves pivots chosen to eliminate unknown forces. If you pick the pivot at a hinge, hinge forces produce zero torque automatically.

5. Strategy for Identifying Torques

When analyzing a rigid system:

  1. Choose a pivot.
  2. Draw r⃗\vec{r} to each force.
  3. Determine sign (CW or CCW).
  4. Compute with rFsin⁡θrF\sin\theta or r⊥Fr_\perp F.

Changing pivots changes individual torques, but the physical rotation of the object doesn’t change.

Your goal in this topic is speed and clarity. You should be able to look at a diagram and immediately classify every force as positive torque, negative torque, or zero torque.

Key Takeaways

Torque is defined about a specific pivot, and changing the pivot changes the torque values.
Only the perpendicular component of force contributes, captured by rFsin⁡θrF\sin\theta.
The lever arm is the perpendicular distance to the line of action, giving τ=r⊥F\tau = r_\perp F.
Forces acting through the pivot always produce zero torque.
Use the right-hand rule carefully by pointing along r⃗\vec{r}, not along the force first.
In 2D problems, counterclockwise is usually positive and clockwise negative, but you must stay consistent.

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