6m left·0%
Reading Time: 6 min
Last Updated: February 25, 2026
Main Ideas: 4
Reading Time: 6 min
Last Updated: February 25, 2026
Main Ideas: 4

Topic 3.5 Notes – Power

Verified for 2027 AP® Physics 1 Exam
Read aloud
Power connects work and energy to time. It tells you how fast energy is transferred into a system, out of a system, or converted from one form to another. In AP Physics 1, you’ll use power to describe engines, motors, lifting, friction, and any situation where energy changes over time.

1. What Power Is

Power is the rate at which energy changes with respect to time.

If energy changes quickly, power is large. If energy changes slowly, power is small.

Mathematically,

Pavg=ΔEΔt P_{\text{avg}} = \frac{\Delta E}{\Delta t}

  • Units: watts (W)
  • 1 W=1 J/s1 \text{ W} = 1 \text{ J/s}
  • Scalar quantity (no direction), but it can be positive or negative depending on whether energy is entering or leaving the system.

Think in terms of systems:

  • Energy transferred into a system
    Example: a motor increasing a car’s kinetic energy.
  • Energy transferred out of a system
    Example: brakes removing kinetic energy.
  • Energy converted within a system
    Example: gravitational potential energy turning into kinetic energy as something falls.

Power answers one question: How fast is the energy changing?

2. The Three Power Equations You Must Know

There are three equations, and choosing the right one depends on what the problem gives you.

a. Average Power from Energy Change

Pavg=ΔEΔt P_{\text{avg}} = \frac{\Delta E}{\Delta t}

Use this when you’re told:

  • A change in kinetic energy
  • A change in potential energy
  • Total energy transferred over a time interval

Example:
A 2 kg object gains 40 J of kinetic energy in 5 s.

Pavg=405=8 W P_{\text{avg}} = \frac{40}{5} = 8 \text{ W}

That means energy is increasing at 8 joules per second.

b. Average Power from Work

Because work is energy transfer by a force, we can also write:

Pavg=WΔt P_{\text{avg}} = \frac{W}{\Delta t}

And since W=ΔEW = \Delta E, this is the same idea in mechanical form.

Use this when:

  • You calculate work using W=Fdcos⁡θW = Fd\cos\theta
  • A force acts over a displacement during a time interval

If a 50 N force pulls an object 10 m in 4 s (force parallel to motion):

W=50×10=500 J W = 50 \times 10 = 500 \text{ J}

Pavg=5004=125 W P_{\text{avg}} = \frac{500}{4} = 125 \text{ W}

c. Instantaneous Power from a Force

This one shows up a lot on conceptual questions:

P=F∥v=Fvcos⁡θ P = F_{\parallel} v = Fv\cos\theta

  • F∥F_{\parallel} is the component of force parallel to velocity
  • vv is instantaneous velocity
  • θ\theta is the angle between force and velocity

This gives power at that instant, not over a time interval.

In the example below, the pulling force is angled above the horizontal. If the box moves horizontally, only the horizontal component of the force does work and contributes to power.

Study guide illustration

Force at an angle to the direction of motion

Only the component of force in the direction of motion transfers energy.

If velocity is zero at that instant, power is zero even if a force exists.

3. How to Interpret the Sign of Power

From P=Fvcos⁡θP = Fv\cos\theta:

Positive Power

  • Force and velocity point in the same general direction.
  • Energy is entering the system.
  • Kinetic energy increases.

Example: a car engine pushing forward while the car moves forward.

Negative Power

  • Force opposite the velocity.
  • Energy leaves the system.
  • Kinetic energy decreases.

Example: friction acting on a sliding box.

Zero Power

  • Force perpendicular to velocity.
  • No energy transfer.

Classic case: centripetal force in circular motion.

Study guide illustration

Centripetal force and tangential velocity in circular motion

In circular motion, the velocity is tangent to the circle and the centripetal force points toward the center. Since they are perpendicular, P=Fvcos⁡90∘=0P = Fv\cos 90^\circ = 0.

The force changes direction of motion, not speed, so kinetic energy stays constant.

This is a favorite multiple-choice trap.

4. Power in Common AP Physics Situations

Lifting at Constant Speed

If you lift an object straight up at constant speed:

  • Net force = 0
  • Applied force = mgmg

P=Fv=mgv P = Fv = mgv

Even though acceleration is zero, power is not zero because energy is being converted from chemical energy to gravitational potential energy.

Moving at Constant Speed on Level Ground

  • Net force = 0
  • Engine force balances friction
  • Kinetic energy is constant

But the engine still produces power:

P=Fv P = Fv

Where does that energy go?
Into thermal energy due to friction and air resistance.

Students often think zero acceleration means zero power. It doesn’t.

Accelerating Object

When net force is not zero:

Wnet=ΔKE W_{\text{net}} = \Delta KE

So

Pavg=ΔKEΔt P_{\text{avg}} = \frac{\Delta KE}{\Delta t}

Power tells you how quickly kinetic energy increases.

Key Takeaways

Power is the rate of energy change, measured in J/s \text{J/s} .
Use Pavg=ΔEΔt P_{\text{avg}} = \frac{\Delta E}{\Delta t} when given an energy change over time.
Use P=Fvcos⁡θ P = Fv\cos\theta when given force and velocity at a specific instant.
Only the component of force parallel to velocity transfers energy.
Zero acceleration does not mean zero power.
A force perpendicular to motion does zero work and produces zero power.
The sign of power tells you whether energy is entering or leaving the system.

AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse this website.

Notes

1 credit used · 5/5 remaining