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Reading Time: 4 min
Last Updated: March 17, 2026
Main Ideas: 4
Reading Time: 4 min
Last Updated: March 17, 2026
Main Ideas: 4

Topic 6.6 Notes – Motion of Orbiting Satellites

Verified for 2027 AP® Physics 1 Exam
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Orbiting satellites move the way they do because gravity is the only force acting and because key conservation laws restrict what can change. In this topic, you connect gravitational force, energy, and angular momentum to explain circular orbits, elliptical orbits, and escape velocity.

1. A Two-Object Gravitational System

A satellite-central object system is just two objects interacting only through gravity.

The gravitational force between them is

Fg=GMmr2 F_g = \frac{GMm}{r^2}

  • MM = mass of the central object
  • mm = mass of the satellite
  • rr = distance between their centers
  • GG = universal gravitational constant

In AP Physics 1, we assume:

  • M≫mM \gg m
  • The central object’s motion is negligible.
  • We analyze the satellite’s motion around a nearly fixed center.

Gravity is a central force. It always points toward the center. That one fact leads to:

  • Curved motion (orbits)
  • Conservation of mechanical energy
  • Conservation of angular momentum

Those conservation laws are what actually control the motion.

2. Gravitational Potential Energy and Total Mechanical Energy

Gravitational Potential Energy

For two objects interacting gravitationally,

Ug=−GMmr U_g = -\frac{GMm}{r}

Important ideas:

  • Ug=0U_g = 0 at infinite separation
  • For any finite rr, UgU_g is negative
  • As rr decreases, UgU_g becomes more negative
  • Energy must be added to separate the objects to infinity

The graph below shows how UgU_g depends on distance rr.

In the diagram, notice the Sun is at one focus of the ellipse, not at the center.

What changes:

  • Speed (fastest at periapsis)
  • Kinetic energy
  • Gravitational potential energy

What stays constant:

  • Total mechanical energy
  • Angular momentum

As the satellite moves closer:

  • UgU_g becomes more negative
  • KK increases

Energy shifts between kinetic and potential, but the total stays fixed.

4. Angular Momentum in Orbits

Angular momentum about the central object is

L=mvr L = mvr

(at points where velocity is perpendicular to radius, like periapsis and apoapsis)

Gravity produces no torque about the center because the force points directly toward it.

So angular momentum is conserved.

That means:

  • If rr decreases → vv must increase
  • If rr increases → vv must decrease

This is the deeper reason satellites speed up when closer. On free-response questions, stating “angular momentum is conserved because gravity is a central force” earns real points.

5. Escape Velocity

Escape velocity is the speed that makes total mechanical energy equal to zero.

Start with

0=12mvesc2−GMmr 0 = \frac{1}{2}mv_{esc}^2 - \frac{GMm}{r}

Solve for vescv_{esc}:

vesc=2GMr v_{esc} = \sqrt{\frac{2GM}{r}}

Notice:

  • Depends on MM and rr
  • Does not depend on satellite mass
  • It is 2\sqrt{2} times the circular orbit speed at the same radius

If gravity is the only force and a satellite reaches escape velocity, it keeps moving away forever, slowing down until its speed approaches zero at infinite distance.

That “speed goes to zero at infinity” idea shows up in conceptual questions more than students expect.

Key Takeaways

In this topic, always assume the central mass is stationary because M≫mM \gg m.
Gravitational potential energy is Ug=−GMmrU_g = -\frac{GMm}{r} and equals zero at infinite separation.
Circular orbits keep rr, vv, KK, UgU_g, EE, and LL constant.
Elliptical orbits keep only total mechanical energy and angular momentum constant.
Speed increases when radius decreases because angular momentum is conserved.
Escape velocity comes from setting total mechanical energy equal to zero, giving vesc=2GM/rv_{esc} = \sqrt{2GM/r}.
Escape speed does not depend on the satellite’s mass.

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Notes

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