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Reading Time: 6 min
Last Updated: March 23, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: March 23, 2026
Main Ideas: 5

Topic 11.5 Notes – Compound Direct Current (DC) Circuits

Verified for 2027 AP® Physics 2 Exam
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You’ll learn how to replace parts of a circuit with an equivalent resistance, how real batteries differ from ideal ones, and how measuring devices can change what you’re trying to measure.

1. Equivalent Resistance in Compound Circuits

In any DC circuit, you can replace a group of resistors with a single equivalent resistance Req R_{\text{eq}} that draws the same total current from the battery.

This works because of:

  • Conservation of charge → current splits and recombines but is conserved.
  • Conservation of energy → total energy per charge from the battery equals total energy lost across resistors.
  • Ohm’s Law V=IR V = IR .

If you can reduce a messy circuit to one resistor, you can immediately find the total current using

Itotal=VReq I_{\text{total}} = \frac{V}{R_{\text{eq}}}

A compound circuit just means it contains both series and parallel parts.

2. Series and Parallel Connections

Series Connections

In a series connection, charge has only one path. Any charge that goes through one resistor must go through all of them.

Study guide illustration

Single-loop series circuit

In the single loop above, notice how the current follows one continuous path through R1R_{1}, R2R_{2}, and R3R_{3}.

Key facts:

  • Same current through each resistor.
  • Voltage divides among resistors.
  • Equivalent resistance: Req=R1+R2+R3+… R_{\text{eq}} = R_{1} + R_{2} + R_{3} + \dots

Why does resistance add? Each resistor adds more opposition in the single path, so total resistance increases.

If you add more resistors in series:

  • Req R_{\text{eq}} increases
  • Total current (for fixed battery voltage) decreases

Parallel Connections

In a parallel connection, charge has multiple paths between the same two points.

Study guide illustration

Three resistors in parallel across a 9 V battery

Each resistor in the diagram is connected across the same top and bottom nodes, so they all share the full 9 V.

Key facts:

  • Same voltage across each branch.
  • Current splits.
  • Lower resistance branch → larger current.
  • Total current = sum of branch currents.

Equivalent resistance:

1Req=1R1+1R2+… \frac{1}{R_{\text{eq}}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \dots

Important result:

Req<smallest individual resistor R_{\text{eq}} < \text{smallest individual resistor}

Adding parallel branches gives charges more paths, which makes it easier for current to flow, so total resistance decreases.

3. How to Analyze Compound Circuits

When circuits mix series and parallel, reduce them step by step.

  1. Find a clear series or parallel group.
    • Series → no branching between them.
    • Parallel → share the same two nodes.
  2. Replace that group with its Req R_{\text{eq}} .
  3. Redraw the simplified circuit.
  4. Repeat until one resistor remains.
  5. Use I=VReq I = \frac{V}{R_{\text{eq}}} .
  6. Work backward:
    • Series → same current.
    • Parallel → same voltage.

On free-response, graders want to see that you identify why something is series or parallel, not just plug numbers into formulas.

4. Real Batteries and Resistive Wires

Most AP problems assume ideal components unless told otherwise.

Ideal assumptions

  • Ideal battery → zero internal resistance.
  • Ideal wires → zero resistance.
  • Terminal voltage = emf E \mathcal{E} .

Wire resistance can usually be ignored because it’s much smaller than resistor values in the circuit. It only matters if the wire is very long, very thin, or the rest of the circuit has very small resistance.

Battery with Internal Resistance

A real battery behaves like an ideal emf source in series with a small internal resistance, often labeled r r .

Study guide illustration

Battery modeled as an emf source in series with internal resistance

That internal resistance is in series with whatever external resistor is connected.

Total resistance:

Rtotal=Rexternal+r R_{\text{total}} = R_{\text{external}} + r

Current:

I=ERexternal+r I = \frac{\mathcal{E}}{R_{\text{external}} + r}

Terminal voltage:

ΔVterminal=E−Ir \Delta V_{\text{terminal}} = \mathcal{E} - Ir

When current flows, some energy is lost as heat inside the battery. So terminal voltage is less than emf.

If I=0 I = 0 (open circuit), then terminal voltage equals emf.

As current increases, the internal drop Ir Ir increases, and terminal voltage decreases. That cause-and-effect explanation shows up often in conceptual questions.

5. Measuring Current and Voltage

Meters are part of the circuit, so they can affect it.

Ammeters

  • Measure current.
  • Must be placed in series.
  • Ideal ammeter → zero resistance.

If it had resistance, it would increase total series resistance and reduce current.

Voltmeters

  • Measure potential difference.
  • Must be placed in parallel.
  • Ideal voltmeter → infinite resistance.

If it allowed current through, it would change how current distributes in the circuit.

AP only expects qualitative reasoning about nonideal meters. Unless stated otherwise, assume meters are ideal.

Key Takeaways

In series, current is the same and Req R_{\text{eq}} adds directly.
In parallel, voltage is the same and Req R_{\text{eq}} is always less than the smallest resistor.
When simplifying compound circuits, reduce step-by-step and redraw each time.
For a real battery, terminal voltage is E−Ir \mathcal{E} - Ir when current flows.
An ammeter must have near-zero resistance; a voltmeter must have very large resistance or they change the circuit.

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Notes

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