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Reading Time: 6 min
Last Updated: July 2, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: July 2, 2026
Main Ideas: 5

Topic 1.8 Notes – Rational Functions and Zeros

Verified for 2027 AP® Precalculus Exam
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Rational functions are quotients of polynomials, so their zeros look familiar at first. The twist is the domain. A value only counts as a zero if it makes the numerator 0 and keeps the denominator nonzero, and that same idea drives rational inequalities too.

What Zeros of a Rational Function Are

A rational function has the form

r(x)=P(x)Q(x) r(x)=\frac{P(x)}{Q(x)}

where P(x)P(x) and Q(x)Q(x) are polynomials and Q(x)≠0Q(x)\ne 0.

A zero means r(a)=0r(a)=0. For any fraction to equal 0, the top must be 0 and the bottom must not be 0. So for rational functions:

  • aa is a zero when P(a)=0P(a)=0 and Q(a)≠0Q(a)\ne 0
  • real zeros come from real zeros of the numerator
  • any value that also makes the denominator 0 is excluded and is not a zero

That domain piece matters a lot. If the denominator is 0, the function is undefined, even if that factor cancels later.

  • Graph connection
    A real zero gives an xx-intercept (a,0)(a,0) only if the function is defined at aa.
  • An undefined input is never a zero and never an xx-intercept.

This graph shows both ideas at once. The function has an xx-intercept at (−2,0)(-2,0), but the factor x−5x-5 cancels and leaves a hole at x=5x=5, so x=5x=5 is excluded instead of being a zero.

Rational function with an x-intercept, a hole, and a vertical asymptote

Finding Zeros Analytically

This is the standard process you’ll use on quizzes and no-calculator work.

  1. Factor the numerator and denominator completely.
  2. Find denominator zeros first. These are excluded values.
  3. Find numerator zeros. These are candidate zeros.
  4. Remove any candidate that is excluded.
  5. Report the remaining real zeros, or the xx-intercepts if asked.

Example:

f(x)=(x+2)(x−5)(x−1)(x−5) f(x)=\frac{(x+2)(x-5)}{(x-1)(x-5)}

  • denominator zeros are x=1,5x=1,5, so both are excluded
  • numerator zeros are x=−2,5x=-2,5
  • x=5x=5 is excluded, so it is not a zero
  • the only zero is x=−2x=-2, so the xx-intercept is (−2,0)(-2,0)

Cancellation rule

You can simplify by canceling common factors, but the restriction stays.

(x−4)2x−4=x−4for x≠4 \frac{(x-4)^2}{x-4}=x-4 \quad \text{for } x\ne 4

The simplified expression has a zero at 4, but the original function is undefined there. So the original rational function has no zero.

Equations rewritten to find zeros

If you see

A(x)B(x)=c \frac{A(x)}{B(x)}=c

rewrite it as

A(x)−cB(x)B(x)=0 \frac{A(x)-cB(x)}{B(x)}=0

Then solve A(x)−cB(x)=0A(x)-cB(x)=0, while keeping B(x)≠0B(x)\ne 0. Multiplying by the denominator is fine only if you track excluded values first.

Zeros from Graphs, Tables, and Technology

Zeros can show up in different forms, but the domain still decides.

  • From a graph
    A zero is where the graph actually touches or crosses the xx-axis.
    An open circle on the xx-axis is not a zero.
  • From a table
    A zero happens when the function value is defined and equals 0.
    Blank, error, or undefined does not count.
  • From technology
    A calculator can approximate numerator zeros, but you still must check the denominator. A graph can hide a missing point.

Solving Rational Inequalities with Zeros

For inequalities like r(x)≥0r(x)\ge 0 or r(x)<0r(x)<0, both numerator and denominator zeros matter because they split the number line.

Boundary values include:

  • numerator zeros that are in the domain
  • denominator zeros, always excluded
  • common zeros of numerator and denominator, still excluded

Sign-chart procedure

For

r(x)=(x−3)(x+1)(x−2)(x+4) r(x)=\frac{(x-3)(x+1)}{(x-2)(x+4)}

solve r(x)≤0r(x)\le 0.

  • numerator zeros: −1,3-1,3
  • denominator zeros: −4,2-4,2

These split the number line into intervals: (−∞,−4)(-\infty,-4), (−4,−1)(-4,-1), (−1,2)(-1,2), (2,3)(2,3), (3,∞)(3,\infty)

Test one point in each interval to get the sign. The sign chart below shows that the negative intervals are:

(−4,−1]∪(2,3] (-4,-1]\cup(2,3]

The brackets happen because ≤0\le 0 includes valid numerator zeros.

Endpoint rules

  • Include numerator zeros only for ≥\ge or ≤\le, and only if they’re in the domain.
  • Exclude numerator zeros for >> or <<.
  • Exclude denominator zeros every time.
  • In interval notation, use brackets only at valid included numerator zeros.

Common Traps and Sign Shortcuts

The most common mistakes are:

  • forgetting the original domain after canceling
  • calling a denominator zero a zero of the function
  • losing a “puncture” in an inequality after canceling a common factor
  • leaving a canceled factor off the number line - the hole is still excluded, even though the sign does not change there

Multiplicity helps with signs:

  • odd multiplicity means the sign changes
  • even multiplicity means the sign stays the same

That works for numerator and denominator factors. Still, if you’re unsure, a full sign chart is safer than doing sign changes in your head.

Key Takeaways

A zero of a rational function happens where the numerator is 0 and the denominator is not 0.
A denominator zero is never a zero of the function and never an xx-intercept.
Canceling factors simplifies the expression but does not remove domain restrictions from the original function.
An open point on the xx-axis is not a zero because the function is undefined there.
For rational inequalities, both numerator and denominator zeros must go on the number line.
Use brackets in interval notation only at valid numerator zeros included by ≥\ge or ≤\le.
Denominator zeros always use parentheses, even if the inequality includes equality.
A common factor can still split the solution into separate intervals even when it cancels.
Odd multiplicity changes sign across a boundary value, and even multiplicity does not.
If a calculator shows a zero, still check whether that xx-value makes the denominator 0.

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Notes

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