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Reading Time: 5 min
Last Updated: August 5, 2026
Main Ideas: 5
Reading Time: 5 min
Last Updated: August 5, 2026
Main Ideas: 5

Topic 3.3 Notes – Sine and Cosine Function Values

Verified for 2027 AP® Precalculus Exam
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Sine and cosine in this topic are coordinates on a circle, not just button names on a calculator. You take an angle in standard position, find where its terminal ray hits a circle centered at the origin, and read cosine from the xx-coordinate and sine from the yy-coordinate.

Sine and Cosine as Circle Coordinates

An angle is in standard position when its vertex is at the origin and its initial side lies on the positive xx-axis. The terminal ray lands on a circle of radius rr.

That intersection point is

P=(rcos⁡θ,  rsin⁡θ) P=(r\cos\theta,\; r\sin\theta)

On the unit circle, where r=1r=1, this becomes

P=(cos⁡θ,sin⁡θ) P=(\cos\theta,\sin\theta)

So the whole idea is simple:

  • cosine = xx-coordinate
  • sine = yy-coordinate
Study guide illustration

Unit circle coordinates

In the diagram, the point on the unit circle has coordinates (x,y)(x,y), so x=cos⁡tx=\cos t and y=sin⁡ty=\sin t.

You also use this backward. If P=(x,y)P=(x,y) is on a circle of radius rr, then

cos⁡θ=xrsin⁡θ=yr \cos\theta=\frac{x}{r} \qquad \sin\theta=\frac{y}{r}

The radius is a scale factor. It multiplies both coordinates, not the angle.

Quick checks that catch lots of errors:

  • signs must match the quadrant
  • each coordinate must stay between −r-r and rr
  • the point must satisfy x2+y2=r2x^2+y^2=r^2

Exact Values You Need to Know

Some angles come straight from the axes.

Axis angles

On the unit circle:

  • 00 and 2π2\pi give (1,0)(1,0)
  • π2\frac{\pi}{2} gives (0,1)(0,1)
  • π\pi gives (−1,0)(-1,0)
  • 3π2\frac{3\pi}{2} gives (0,−1)(0,-1)

On radius rr, just scale those to (r,0)(r,0), (0,r)(0,r), (−r,0)(-r,0), (0,−r)(0,-r).

Special-angle families

These come from special right triangles.

FamilyTriangleUnit-circle magnitudes
multiples of π4\frac{\pi}{4}45∘45^\circ-45∘45^\circ-90∘90^\circ22,22\frac{\sqrt2}{2}, \frac{\sqrt2}{2}
multiples of π6\frac{\pi}{6}30∘30^\circ-60∘60^\circ-90∘90^\circcos⁡=32, sin⁡=12\cos=\frac{\sqrt3}{2},\ \sin=\frac12
multiples of π3\frac{\pi}{3}same triangle, roles reversedcos⁡=12, sin⁡=32\cos=\frac12,\ \sin=\frac{\sqrt3}{2}

This unit circle collects the exact coordinates for the axis angles and the most common special angles in both degrees and radians.

Study guide illustration

Common exact values on the unit circle

Keep exact values in radical form, not decimals, unless the question asks for an approximation.

Quadrants, Reference Angles, and Coterminal Angles

A reference angle is the acute angle the terminal ray makes with the xx-axis. It gives the coordinate magnitudes. The quadrant gives the signs.

  • Quadrant I: (+,+)(+,+)
  • Quadrant II: (−,+)(-,+)
  • Quadrant III: (−,−)(-,-)
  • Quadrant IV: (+,−)(+,-)

Since cosine is xx and sine is yy, those sign patterns follow automatically.

Coterminal angles differ by 2πk2\pi k, where kk is any integer. They land on the same terminal ray, so they have the same sine and cosine.

Negative angles often get easier if you rewrite them in [0,2π)[0,2\pi). For example, −3π4-\frac{3\pi}{4} is coterminal with 5π4\frac{5\pi}{4}.

One easy trap: some multiples of π6\frac{\pi}{6} are actually axis angles, like π2\frac{\pi}{2}. Read those directly from the axes.

Finding a Point or a Trig Value from an Angle

Here’s the full path the test expects you to be able to do cleanly:

  1. Decide the case: axis angle, π/4\pi/4 family, π/6\pi/6 family, or π/3\pi/3 family.
  2. If needed, rewrite to a coterminal angle in one revolution.
  3. Find the quadrant or see if it lies on an axis.
  4. If it is in a quadrant, find the reference angle.
  5. Use the right special-angle magnitudes.
  6. Apply signs from the quadrant.
  7. If the radius is not 1, multiply both coordinates by rr.

Example. 5π6\frac{5\pi}{6} on radius 88:

  • reference angle =π6= \frac{\pi}{6}
  • QII gives signs (−,+)(-,+)
  • unit-circle point =(−32,12)= \left(-\frac{\sqrt3}{2}, \frac12\right)
  • radius 8 gives (−43,4)(-4\sqrt3, 4)

If you’re given a point, work backward.

Example. P=(−5,12)P=(-5,12):

  • r=(−5)2+122=13r=\sqrt{(-5)^2+12^2}=13
  • cos⁡θ=−513\cos\theta=\frac{-5}{13}
  • sin⁡θ=1213\sin\theta=\frac{12}{13}

If sin⁡θ=−32\sin\theta=-\frac{\sqrt3}{2} and 0≤θ<2π0\le \theta<2\pi, then y=−32y=-\frac{\sqrt3}{2}, so the angles are 4π3\frac{4\pi}{3} and 5π3\frac{5\pi}{3}.

Common Mistakes and Fast Self-Checks

ExampleWhat to watch
(−5,12)(-5,12) on a circlefind rr first, then divide by rr
5π6\frac{5\pi}{6} on radius 8QII makes cosine negative, sine positive
−3π4-\frac{3\pi}{4} on radius 6rewrite as 5π4\frac{5\pi}{4}, then scale to (−32,−32)(-3\sqrt2,-3\sqrt2)
sin⁡θ=−32\sin\theta=-\frac{\sqrt3}{2} on 0≤θ<2π0\le\theta<2\pitwo angles, both below the xx-axis

Key Takeaways

(cos⁡θ,sin⁡θ)(\cos\theta,\sin\theta) always means xx then yy.
For a circle of radius rr, the point is (rcos⁡θ,rsin⁡θ)(r\cos\theta,r\sin\theta), so rr multiplies both coordinates.
Axis angles like 0,π2,π,3π20,\frac{\pi}{2},\pi,\frac{3\pi}{2} should be read directly from the axes.
The π/6\pi/6 and π/3\pi/3 families switch which function gets 12\frac12 and which gets 32\frac{\sqrt3}{2}.
A negative angle does not force negative sine or cosine; the terminal ray decides the signs.
If your final point does not satisfy x2+y2=r2x^2+y^2=r^2, something went wrong.

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