6m left·0%
Reading Time: 6 min
Last Updated: July 2, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: July 2, 2026
Main Ideas: 5

Topic 1.9 Notes – Rational Functions and Vertical Asymptotes

Verified for 2027 AP® Precalculus Exam
Read aloud
Rational functions can break in two different ways at denominator zeros. In this topic, you’re sorting out which zeros create vertical asymptotes and which ones only create holes, then describing what the graph does on each side of an asymptote using one-sided limits.

What Vertical Asymptotes Are

A rational function has the form

r(x)=P(x)Q(x) r(x)=\frac{P(x)}{Q(x)}

where P(x)P(x) and Q(x)Q(x) are polynomials. Its domain excludes any real xx-value that makes Q(x)=0Q(x)=0.

A vertical asymptote happens at x=ax=a when the outputs blow up near that input. In symbols, that means one or both one-sided limits are infinite:

  • lim⁡x→a−r(x)=∞\lim_{x\to a^-} r(x)=\infty or lim⁡x→a−r(x)=−∞\lim_{x\to a^-} r(x)=-\infty
  • lim⁡x→a+r(x)=∞\lim_{x\to a^+} r(x)=\infty or lim⁡x→a+r(x)=−∞\lim_{x\to a^+} r(x)=-\infty

That is about behavior near x=ax=a. It does not mean r(a)=∞r(a)=\infty. In fact, r(a)r(a) is undefined there.

Here is a typical example. The graph shows vertical asymptotes at x=−1x=-1 and x=2x=2, with the function values growing without bound as xx approaches those inputs from one or both sides.

Rational function with vertical asymptotes

Vertical asymptotes come from real zeros of the denominator after shared factors are accounted for. Only real zeros matter here, because only real xx-values can give vertical lines on the real graph.

Which Denominator Zeros Become Vertical Asymptotes

A denominator zero is only the starting point. You have to compare it with the numerator.

For a real zero x=ax=a, there are four cases:

  • Denominator zero only →\rightarrow vertical asymptote
  • Common zero, larger multiplicity in denominator →\rightarrow vertical asymptote
  • Common zero, equal multiplicities →\rightarrow hole, no vertical asymptote
  • Common zero, larger multiplicity in numerator →\rightarrow no vertical asymptote, but x=ax=a is still excluded from the original function

The key idea is the factor (x−a)(x-a). If, after cancellation, some (x−a)(x-a) is still left in the denominator, then x=ax=a is a vertical asymptote.

One common trap is seeing 0/00/0 after substitution and deciding too fast. 0/00/0 only tells you there is a shared zero. It does not tell you whether the result is an asymptote or a hole.

How to Find Vertical Asymptotes from an Equation

This is the full process you’ll use on quizzes and FRQs.

  1. Factor the numerator and denominator.
  2. List the real zeros of the denominator.
  3. Compare multiplicities at any shared zero.
  4. Cancel common factors to analyze the graph.
  5. Whatever real denominator factors remain give vertical asymptotes.

Example:

(x−2)(x+3)(x−5)(x−2)3(x+1)(x−5) \frac{(x-2)(x+3)(x-5)}{(x-2)^3(x+1)(x-5)}

Denominator zeros are x=2x=2, x=−1x=-1, and x=5x=5.

  • At x=2x=2, one (x−2)(x-2) cancels, but (x−2)2(x-2)^2 remains downstairs →\rightarrow asymptote
  • At x=−1x=-1, only the denominator is zero →\rightarrow asymptote
  • At x=5x=5, (x−5)(x-5) cancels completely →\rightarrow hole, not an asymptote

So the vertical asymptotes are

x=2andx=−1 x=2 \quad \text{and} \quad x=-1

The simplified form is

x+3(x−2)2(x+1) \frac{x+3}{(x-2)^2(x+1)}

but remember x=5x=5 is still excluded from the original domain.

Determining the Direction on Each Side

Once you know x=ax=a is a vertical asymptote, you still need the direction on each side.

Use the reduced factored form and check signs near aa.

  • If the remaining power of (x−a)(x-a) in the denominator is odd, the sign changes across aa. The one-sided limits have opposite signs.
  • If the remaining power is even, the sign stays the same across aa. The one-sided limits have the same sign.

For

r(x)=x+3(x−2)2(x+1) r(x)=\frac{x+3}{(x-2)^2(x+1)}

  • At x=−1x=-1, the factor (x+1)(x+1) has odd power, so signs switch:

lim⁡x→−1−r(x)=−∞,lim⁡x→−1+r(x)=∞ \lim_{x\to -1^-} r(x)=-\infty,\qquad \lim_{x\to -1^+} r(x)=\infty

  • At x=2x=2, the factor (x−2)2(x-2)^2 has even power, so both sides match:

lim⁡x→2−r(x)=∞,lim⁡x→2+r(x)=∞ \lim_{x\to 2^-} r(x)=\infty,\qquad \lim_{x\to 2^+} r(x)=\infty

Reading Vertical Asymptotes from Graphs, Tables, and Wording

From a graph, look for branches approaching a vertical line x=ax=a and shooting up or down without bound.

From a table, look for inputs getting closer to the same number from left and right while outputs become very large positive or negative.

From words:

  • “increase without bound as inputs approach aa from the right” means lim⁡x→a+r(x)=∞\lim_{x\to a^+} r(x)=\infty
  • “decrease without bound as inputs approach aa from the left” means lim⁡x→a−r(x)=−∞\lim_{x\to a^-} r(x)=-\infty

Common mistakes:

  • Calling every denominator zero an asymptote
  • Forgetting multiplicities
  • Treating a hole like an asymptote
  • Writing r(a)=∞r(a)=\infty
  • Trusting a graphing window more than the algebra

Key Takeaways

A denominator zero gives a vertical asymptote only if a factor involving that zero remains in the denominator after cancellation.
The expression 0/00/0 does not tell you whether you have a hole or a vertical asymptote.
Equal multiplicities at a shared zero give a hole, not an asymptote.
A canceled denominator zero is still excluded from the original domain.
If the remaining denominator power at x=ax=a is odd, the one-sided limits have opposite signs.
If the remaining denominator power at x=ax=a is even, the one-sided limits have the same sign.
Saying lim⁡x→a±r(x)=±∞\lim_{x\to a^\pm} r(x)=\pm\infty describes nearby behavior, not a function value at x=ax=a.

AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse this website.

Notes

1 credit used · 5/5 remaining