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Reading Time: 6 min
Last Updated: July 23, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: July 23, 2026
Main Ideas: 5

Topic 2.11 Notes – Logarithmic Functions

Verified for 2027 AP® Precalculus Exam
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Logarithmic functions are the inverses of exponential functions, so their graphs, points, and behavior all come from that relationship. In this topic, you need to recognize what a logarithm looks like, how its graph behaves, and how transformations change the domain, asymptote, and direction of the graph.

What Logarithmic Functions Are

A logarithmic function in general form is

f(x)=alog⁡bx f(x)=a\log_b x

with a≠0a\ne 0, b>0b>0, and b≠1b\ne 1.

The core meaning is

log⁡bx=y  ⟺  by=x \log_b x=y \iff b^y=x

So a logarithm asks, “What exponent on base bb gives xx?”

Because logs and exponentials are inverses, their graphs reflect across y=xy=x, as in the graph of 2x2^x and log⁡2x\log_2 x below.

Study guide illustration

Useful anchor points for y=log⁡bxy=\log_b x:

  • (1,0)(1,0) because log⁡b1=0\log_b 1=0
  • (b,1)(b,1)
  • (1b,−1)\left(\frac1b,-1\right)

For f(x)=alog⁡bxf(x)=a\log_b x, those become:

  • (1,0)(1,0)
  • (b,a)(b,a)
  • (1b,−a)\left(\frac1b,-a\right)

A couple names you should recognize:

  • Common log means log⁡x=log⁡10x\log x=\log_{10}x
  • Natural log means ln⁡x=log⁡ex\ln x=\log_e x

In general form, the domain is (0,∞)(0,\infty) and the range is (−∞,∞)(-\infty,\infty).

Intercepts:

  • xx-intercept is always (1,0)(1,0)
  • No yy-intercept, because x=0x=0 is not in the domain

If the argument is changed, like log⁡b(kx+c)\log_b(kx+c), the domain comes from the full argument being positive:

kx+c>0 kx+c>0

How the Graph Behaves

Logs are monotonic on their whole domain. They never switch from increasing to decreasing.

Increasing and decreasing

For y=log⁡bxy=\log_b x:

  • if b>1b>1, it is increasing
  • if 0<b<10<b<1, it is decreasing

If a<0a<0, multiplying by aa reflects across the xx-axis, so the direction reverses.

Compact test for f(x)=alog⁡bxf(x)=a\log_b x:

  • increasing when aln⁡b>0\frac{a}{\ln b}>0
  • decreasing when aln⁡b<0\frac{a}{\ln b}<0

Concavity

For the parent graph:

  • if b>1b>1, it is concave down
  • if 0<b<10<b<1, it is concave up

If a<0a<0, concavity reverses too.

That gives an important general-form pairing:

  • increasing logs are concave down
  • decreasing logs are concave up

Extrema and inflection points

On the full domain, logarithmic functions have:

  • no local or absolute extrema
  • no inflection points

On a closed interval, any max or min happens at an endpoint.

Asymptotes, End Behavior, and Transformed Arguments

In general form, the vertical asymptote is

x=0 x=0

You only approach it from the right, so use x→0+x\to 0^+, not a two-sided limit.

For an increasing log:

lim⁡x→0+f(x)=−∞lim⁡x→∞f(x)=∞ \lim_{x\to 0^+}f(x)=-\infty \qquad \lim_{x\to\infty}f(x)=\infty

For a decreasing log:

lim⁡x→0+f(x)=∞lim⁡x→∞f(x)=−∞ \lim_{x\to 0^+}f(x)=\infty \qquad \lim_{x\to\infty}f(x)=-\infty

There is no horizontal asymptote because outputs stay unbounded.

For

g(x)=alog⁡b(kx+c)+d g(x)=a\log_b(kx+c)+d

here is what changes:

  • domain comes from kx+c>0kx+c>0
  • vertical asymptote is where kx+c=0kx+c=0, so

x=−ck x=-\frac{c}{k}

  • the graph exists only on the side where kx+c>0kx+c>0
  • dd shifts up or down, but does not change range, monotonicity, or concavity
  • if k<0k<0, increasing/decreasing reverses, but concavity does not

So transformed logs can be any of these:

  • increasing, concave down
  • decreasing, concave down
  • increasing, concave up
  • decreasing, concave up

Example:

g(x)=log⁡2(6−2x) g(x)=\log_2(6-2x)

Domain:

6−2x>0⇒x<3 6-2x>0 \Rightarrow x<3

So the asymptote is x=3x=3, and the graph is on the left of it. Since 6−2x6-2x decreases as xx increases, the graph is decreasing. It stays concave down. The graph below also shows the x-intercept at (52,0)\left(\frac52,0\right).

Recognizing Logarithmic Structure from Tables, Equations, and Graphs

In an equation, the variable is inside a logarithm, and the full argument must stay positive.

In a graph, look for these clues:

  • one side of a vertical asymptote only
  • monotonic on the whole domain
  • one concavity only
  • unbounded near the asymptote and also at the far end
  • no extrema and no inflection points

In a table, the hallmark is this: equal output changes match proportional inputs.

Example for f(x)=2log⁡3xf(x)=2\log_3 x:

  • outputs −2,0,2,4-2,0,2,4
  • inputs 13,1,3,9\frac13,1,3,9

Each output goes up by 2, and each input gets multiplied by 3.

With shifted logs, raw xx-values often are not proportional. The proportional pattern may appear only after adjusting for the asymptote, like distances from it.

Common Mistakes on the Test

  • Saying the domain is all real numbers for general form
  • Giving a yy-intercept at x=0x=0
  • Mixing up “undefined at 00” with the one-sided limit as x→0+x\to 0^+
  • Using a two-sided limit at 00
  • Assuming every log is increasing
  • Keeping the general-form increase/concavity pairing after a horizontal reflection inside the argument
  • Checking raw xx-values for proportionality in shifted logs instead of distances from the vertical asymptote

Key Takeaways

For f(x)=alog⁡bxf(x)=a\log_b x, the domain is always x>0x>0 and the range is all real numbers.
Every general-form logarithm has xx-intercept (1,0)(1,0) and no yy-intercept.
The asymptote for alog⁡bxa\log_b x is x=0x=0, and limits there are one-sided as x→0+x\to 0^+.
In general form, increasing logs are concave down and decreasing logs are concave up.
For alog⁡b(kx+c)+da\log_b(kx+c)+d, the domain and asymptote come from solving kx+c>0kx+c>0 and kx+c=0kx+c=0.
A negative inside factor kk flips increasing/decreasing, but it does not flip concavity.
In tables, logarithmic structure shows up when equal output changes match multiplicative changes in the relevant input.

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