6m left·0%
Reading Time: 6 min
Last Updated: August 26, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: August 26, 2026
Main Ideas: 5

Topic 2.9 Notes – Parameters of Random Variables

Verified for 2027 AP® Statistics Exam
Read aloud
This topic is about the numerical summaries of a discrete random variable’s probability distribution. You’re taking a random process with countable outcomes, attaching probabilities to those outcomes, and then describing its center and spread with the mean, variance, and standard deviation.

What the Parameters of a Discrete Random Variable Are

A discrete random variable XX has countable possible values, and each value has a probability. Those probabilities must all be between 0 and 1 and add up to 1.

A parameter is a fixed numerical characteristic of a population or probability distribution. For a discrete random variable XX, the main parameters here are:

  • Mean E(X)=μXE(X)=\mu_X
  • Variance V(X)=σX2V(X)=\sigma_X^2
  • Standard deviation SD(X)=σXSD(X)=\sigma_X

The subscript matters. μX\mu_X means the mean of the distribution of that random variable XX.

One easy confusion to avoid:

  • Outcome of XX changes from trial to trial.
  • Parameters of the distribution stay fixed.
  • Statistics like xˉ\bar{x} and ss come from sample data, so they can change from sample to sample.

Mean, Variance, and Standard Deviation

Mean or expected value

The expected value is the probability-weighted average of the possible values.

μX=E(X)=∑xiP(X=xi) \mu_X=E(X)=\sum x_iP(X=x_i)

That means each outcome gets multiplied by how likely it is, then you add.

  • It gives the long-run average over many repetitions.
  • It has the same units as XX.
  • It is not the guaranteed result of one trial.
  • It might not be the most likely value.
  • It does not even have to be a possible outcome.

You can also think of the mean as the distribution’s balance point.

Mean as a distribution’s balance point

Variance

Variance measures how spread out the distribution is around the mean.

σX2=V(X)=∑(xi−μX)2P(X=xi) \sigma_X^2=V(X)=\sum (x_i-\mu_X)^2P(X=x_i)

The squared deviations do two jobs:

  • they keep positive and negative deviations from canceling
  • they give more weight to values far from the mean

Variance has squared units, so it is usually less meaningful in context.

Standard deviation

Standard deviation is the square root of variance.

σX=SD(X)=∑(xi−μX)2P(X=xi) \sigma_X=SD(X)=\sqrt{\sum (x_i-\mu_X)^2P(X=x_i)}

This is the typical distance of values of XX from the mean in the long run. It has the same units as XX.

  • Larger σX\sigma_X means more spread
  • σX=0\sigma_X=0 means XX always takes one value

Equivalent variance shortcut

Sometimes arithmetic is faster with

V(X)=E(X2)−[E(X)]2 V(X)=E(X^2)-[E(X)]^2

where

E(X2)=∑xi2P(X=xi) E(X^2)=\sum x_i^2P(X=x_i)

Use this when the numbers are annoying, but the original variance formula shows the meaning better.

How to Calculate Them from a Probability Distribution

Suppose XX is the number of late buses in a morning, with:

  • 0 with probability 0.35
  • 1 with probability 0.40
  • 2 with probability 0.20
  • 3 with probability 0.05

First check it’s valid. All probabilities are between 0 and 1, and 0.35+0.40+0.20+0.05=10.35+0.40+0.20+0.05=1.

A table like this helps organize the mean and variance calculations.

Probability distribution table with mean, variance, and standard deviation calculations

Then calculate:

  1. Mean

    μX=0(0.35)+1(0.40)+2(0.20)+3(0.05)=0.95 \mu_X=0(0.35)+1(0.40)+2(0.20)+3(0.05)=0.95

  2. Variance using the exact mean

    σX2=(0−0.95)2(0.35)+(1−0.95)2(0.40)+(2−0.95)2(0.20)+(3−0.95)2(0.05)=0.7475 \sigma_X^2=(0-0.95)^2(0.35)+(1-0.95)^2(0.40)+(2-0.95)^2(0.20)+(3-0.95)^2(0.05)=0.7475

  3. Standard deviation

    σX=0.7475≈0.865 \sigma_X=\sqrt{0.7475}\approx0.865

On technology, put values in one list and probabilities in a weight/frequency list. Use weighted 1-variable stats and choose population standard deviation σx\sigma_x, not sample sxs_x.

How to Interpret the Mean and Standard Deviation

Your answer has to be in context.

  • Mean
    Over many mornings, the long-run average number of late buses will be about 0.950.95 late buses per morning.

  • Standard deviation
    Over many mornings, the number of late buses will typically differ from its mean of 0.950.95 by about 0.8650.865 bus.

Together, these tell you:

  • mean gives center
  • standard deviation gives spread around that center

They do not tell you the full shape by themselves.

Common Mistakes and Exam Traps

  • Saying the expected value is what will happen on one trial
  • Treating the expected value as the most likely outcome
  • Forgetting the expected value can be non-integer even if XX counts things
  • Giving variance when the question asked for standard deviation
  • Rounding μX\mu_X too early before finding σX\sigma_X
  • Leaving out context, units, or long-run language in interpretation
  • Mixing up distribution parameters μX,σX\mu_X,\sigma_X with sample statistics xˉ,s\bar{x},s

Key Takeaways

E(X)E(X) is a probability-weighted average, so it describes the long-run average outcome of the random process.
The expected value can be 2.42.4 or 0.950.95 even when the random variable only takes whole-number values.
The total of the (xi−μX)2P(X=xi)(x_i-\mu_X)^2P(X=x_i) column is the variance V(X)V(X), and you still need a square root to get SD(X)SD(X).
Use the exact mean in variance and standard deviation calculations, then round at the end.
On a calculator, use weighted one-variable statistics and report σx\sigma_x, not sxs_x.
A full interpretation must name the variable, the setting, the units, and the long-run idea.

AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse this website.

Notes

1 credit used · 5/5 remaining