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Reading Time: 6 min
Last Updated: March 30, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: March 30, 2026
Main Ideas: 5

Topic 5.8 Notes – Sketching Graphs of Functions and Their Derivatives

Verified for 2027 AP® Calculus AB Exam
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Instead of guessing what a function looks like, you use f′f' and f′′f'' to justify where it increases, decreases, has extrema, and changes concavity. This is where everything from Unit 5 comes together.

How Derivatives Determine the Shape of a Graph

Think of it in layers:

  • f(x)f(x) → position (the graph itself)
  • f′(x)f'(x) → slope of the graph
  • f′′(x)f''(x) → how the slope is changing

From that, almost everything follows.

What f′f' tells you

  • If f′(x)>0f'(x) > 0, the function is increasing.
  • If f′(x)<0f'(x) < 0, the function is decreasing.
  • If f′(x)=0f'(x) = 0 or undefined (and ff exists), that’s a critical point.
  • If f′f' changes sign:
    • +→−+\to- → local maximum
    • −→+-\to+ → local minimum

What f′′f'' tells you

  • If f′′(x)>0f''(x) > 0, the graph is concave up (cup shape).
  • If f′′(x)<0f''(x) < 0, the graph is concave down (cap shape).
  • If f′′f'' changes sign → point of inflection.

Here’s how those ideas connect between a function and its derivative. In the diagrams, notice how the turning points of the original graph line up with where the derivative crosses the x-axis, and how positive and negative regions of f′f' match increasing and decreasing behavior.

On AP questions, you’re often asked to justify conclusions using this logic, not just state them.

The Complete Graph Sketching Checklist

When you’re given a formula for ff, build the graph in a logical order.

1. Domain and Continuity

  • Polynomials → domain is all real numbers.
  • Rational functions → denominator cannot be zero.
  • Check for holes or vertical asymptotes.

If the function isn’t defined somewhere, that affects everything else.

2. Intercepts and Symmetry

  • x-intercepts solve f(x)=0f(x)=0.
  • y-intercept compute f(0)f(0).
  • Even symmetry: f(−x)=f(x)f(-x)=f(x)
  • Odd symmetry: f(−x)=−f(x)f(-x)=-f(x)

These give anchor points before calculus even starts.

3. Critical Points from f′f'

  1. Find f′(x)f'(x).
  2. Solve f′(x)=0f'(x)=0.
  3. Include where f′f' is undefined but ff exists.

These x-values divide the graph into intervals for sign testing.

4. Increasing and Decreasing

Pick a test value in each interval between critical points.

  • If f′>0f'>0 → increasing
  • If f′<0f'<0 → decreasing

That sign change classifies extrema automatically.

5. Concavity and Inflection Points

  1. Find f′′(x)f''(x).
  2. Solve f′′(x)=0f''(x)=0 or undefined.
  3. Test signs on either side.

No sign change means no inflection point, even if f′′=0f''=0. That’s a common trap.

First vs Second Derivative Tests

You have two ways to classify extrema.

First Derivative Test

Look at the sign change of f′f'.

  • Works every time if signs are clear.
  • Especially useful on FRQs where you must justify behavior.

Second Derivative Test

At a critical point where f′=0f'=0:

  • f′′>0f''>0 → local minimum
  • f′′<0f''<0 → local maximum
  • f′′=0f''=0 → inconclusive

Faster, but only works if f′′≠0f''\neq 0.

Reading Information from Graphs of f′f' and f′′f''

This shows up constantly on quizzes and the AP exam.

If you’re given the graph of f′f'

When you’re handed a graph of f′f', your job is to translate what you see into behavior of ff.

From a graph like this:

  • Where f′f' is above the x-axis → ff increasing.
  • Where below → ff decreasing.
  • Where f′f' crosses the axis → possible extrema of ff.
  • If it just touches and turns around → horizontal tangent, not necessarily an extremum.

Students often confuse where f′=0f'=0 with where f=0f=0. Totally different ideas.

If you’re given the graph of f′′f''

  • Above x-axis → concave up.
  • Below x-axis → concave down.
  • Sign change → inflection point.

Remember, inflection requires a sign change, not just touching zero.

Connecting All Representations

AP questions love mixing representations:

  • Analytical: formulas for ff, f′f', f′′f''
  • Numerical: tables of values for f′f'
  • Graphical: graphs of f′f' or f′′f''

You should be able to move between them smoothly.

Example from a table:
If a table shows f′f' changing from negative to positive at x=3x=3, you can justify that ff has a local minimum at x=3x=3. That justification language matters on FRQs.

Key Takeaways

A critical point requires f′=0f'=0 or undefined, but ff must exist there.
f′′=0f''=0 alone does not guarantee an inflection point.
Where f′f' changes sign, ff has a relative extremum.
Where f′′f'' changes sign, ff has an inflection point.
The graph of f′f' tells you about increasing and decreasing; the graph of f′′f'' tells you about concavity.
Never confuse where f(x)=0f(x)=0 with where f′(x)=0f'(x)=0.

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Notes

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