6m left·0%
Reading Time: 6 min
Last Updated: March 19, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: March 19, 2026
Main Ideas: 5

Topic 7.1 Notes – Modeling Situations with Differential Equations

Verified for 2027 AP® Calculus AB Exam
Read aloud
Instead of just finding a derivative, you’ll use derivatives to represent real-world rates and translate verbal descriptions into mathematical relationships. The focus here is building the equation that describes how something changes.

What a Differential Equation Is in a Modeling Context

A differential equation is an equation that relates a function and one or more of its derivatives.

In AP Calculus AB, that usually looks like:

dydx=expression involving x and/or y \frac{dy}{dx} = \text{expression involving } x \text{ and/or } y

So you’re connecting:

  • A quantity (like yy, PP, VV, etc.)
  • Its rate of change (a derivative)
  • The independent variable (often time tt)

If you see “rate of change,” your brain should immediately think derivative.

In modeling, the derivative isn’t just a slope from a graph. It represents something real:

  • population growth → dPdt\frac{dP}{dt}
  • water leaking from a tank → dVdt\frac{dV}{dt}
  • temperature changing → dTdt\frac{dT}{dt}

Differential equations describe how something changes, not what it equals.

Translating Verbal Statements into Differential Equations

Most questions in this topic are translation problems. You’re turning English into calculus.

Here’s the structure almost every time:

Step-by-Step Translation

  1. Identify the changing quantity
    That becomes the dependent variable.
    “The rate of change of mass” → dMdt\frac{dM}{dt}
  2. Identify the independent variable
    Usually time tt, but sometimes xx, distance, etc.
  3. Spot proportional language
    • “Proportional to”
    • “Inversely proportional to”
    • “Proportional to the square of”
    • “Proportional to the product of”
  4. Introduce a constant of proportionality kk
    Always include kk. Never assume it’s 1.

Common Proportional Relationships

Direct Proportionality

“The rate of change of RR is proportional to xx.”

dRdt=kx \frac{dR}{dt} = kx

If it says proportional to the product:

dRdt=kxy \frac{dR}{dt} = kxy

If proportional to a power:

dydx=kx3 \frac{dy}{dx} = kx^3

Inverse Proportionality

“The rate of change of SS is inversely proportional to xx.”

dSdt=kx \frac{dS}{dt} = \frac{k}{x}

Direct means multiply.
Inverse means divide.

That distinction is one of the most common quiz mistakes.

Proportional to Itself

“The rate of change of PP is proportional to PP.”

dPdt=kP \frac{dP}{dt} = kP

This is the foundation of exponential growth and decay (you’ll solve these later).

Finding the Constant of Proportionality kk

Often you’re given specific numerical information.

Example:

“The rate of change of temperature TT is proportional to the square of time tt. When t=2t = 2, the temperature is increasing at 12 degrees per minute.”

Step 1: Write the general equation

dTdt=kt2 \frac{dT}{dt} = kt^2

Step 2: Plug in given values

12=k(22) 12 = k(2^2)

12=4k 12 = 4k

Step 3: Solve for kk

k=3 k = 3

Final model:

dTdt=3t2 \frac{dT}{dt} = 3t^2

Notice we substituted into the derivative, not into TT. That’s a common place students slip up.

On free-response questions, you’ll usually earn a point for the correct differential equation and another for correctly finding kk.

Recognizing the Structure of These Problems

Almost every modeling question in this topic follows this pattern:

  1. A quantity is changing.
  2. The problem describes how its rate depends on something.
  3. The relationship is proportional (direct or inverse).
  4. You write the differential equation.
  5. Sometimes you determine kk.

If you train yourself to think through those steps in order, these problems become very mechanical. Here’s a quick visual summary of the logic:

Modeling differential equations workflow

That’s the whole process. On exam day, you want this flow in your head so you can move from the words to the equation quickly and confidently.

Multiple-choice questions often test whether you picked the correct structure, especially distinguishing between dydt=ky\frac{dy}{dt} = ky and dydt=ky\frac{dy}{dt} = \frac{k}{y}.

Common Mistakes That Cost Points

  • Writing y=kxy = kx when the problem says “rate of change” (you forgot the derivative).
  • Forgetting the constant kk.
  • Mixing up direct and inverse proportionality.
  • Using the wrong variable in the derivative (writing dSdx\frac{dS}{dx} when the problem says “with respect to time”).

Be precise with notation. The AP graders care about it.

Key Takeaways

A differential equation connects a function and its derivative, usually modeling a real-world rate of change.
“Rate of change” always means write a derivative like dQdt\frac{dQ}{dt}.
“Proportional to” means multiply by the expression and include kk; “inversely proportional” means divide by it.
When given numerical information, substitute into the derivative equation to solve for kk, not into the original function.
If the rate is proportional to the function itself, the model has the form dydt=ky\frac{dy}{dt} = ky, which leads to exponential behavior later.

AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse this website.

Notes

1 credit used · 5/5 remaining