5m left·0%
Reading Time: 5 min
Last Updated: March 26, 2026
Main Ideas: 5
Reading Time: 5 min
Last Updated: March 26, 2026
Main Ideas: 5

Topic 10.7 Notes – Alternating Series Test for Convergence

Verified for 2027 AP® Calculus BC Exam
Read aloud
These are series whose terms switch signs back and forth. The test gives you two specific conditions that, when satisfied, guarantee convergence.

What an Alternating Series Is

An alternating series has terms that change sign: positive, negative, positive, negative, and so on.

Common ways this shows up:

∑(−1)nan,∑(−1)n+1an,∑cos⁡(nπ) an \sum (-1)^n a_n, \quad \sum (-1)^{n+1} a_n, \quad \sum \cos(n\pi)\, a_n

Since cos⁡(nπ)=(−1)n\cos(n\pi) = (-1)^n, trig expressions can hide alternating behavior.

When you apply the Alternating Series Test, you rewrite the series in the form

∑(−1)nanor∑(−1)n+1an \sum (-1)^n a_n \quad \text{or} \quad \sum (-1)^{n+1} a_n

where:

  • an>0a_n > 0
  • ana_n represents the magnitude only (ignore the sign)

You always analyze the behavior of ana_n, not the signed term.

The Alternating Series Test

The Alternating Series Test (AST) says:

An alternating series ∑(−1)nan\sum (-1)^n a_n or ∑(−1)n+1an\sum (-1)^{n+1} a_n converges if:

lim⁡n→∞an=0 \lim_{n\to\infty} a_n = 0

and
ana_n is decreasing (eventually decreasing is enough).

That’s it. Two conditions.

What each condition means

  • Limit equals 0
    If lim⁡an≠0\lim a_n \neq 0, the series diverges immediately by the nth-term test.
    This overrides everything else.
  • Decreasing
    You must show an+1<ana_{n+1} < a_n for large nn.
    You can:
    • Compare an+1a_{n+1} and ana_n, or
    • Treat ana_n as f(x)f(x) and show f′(x)<0f'(x) < 0

If both conditions hold, you conclude:
“Therefore, the series converges by the Alternating Series Test.”

Important: AST proves convergence only. It does not prove divergence unless the limit condition fails.

Applying the Alternating Series Test

Here’s the clean process you’ll use on quizzes and FRQs:

  1. Confirm it alternates
    • Look for (−1)n(-1)^n, (−1)n+1(-1)^{n+1}, or cos⁡(nπ)\cos(n\pi).
  2. Identify ana_n
    Remove the alternating factor and make sure what remains is positive.
  3. Check the limit
    • Compute lim⁡an\lim a_n.
    • If not 0 → stop. Diverges.
  4. Check decreasing behavior
    • Compare successive terms, or
    • Take a derivative.
  5. State the test clearly in your conclusion

On free response, skipping the “decreasing” justification costs points. Writing only “limit = 0” is not enough.

Typical Patterns You’ll See

Rational expressions

Example structure:

an=n3n3+5 a_n = \frac{n^3}{n^3 + 5}

If numerator and denominator have the same degree, the limit is a nonzero constant → diverges immediately.

If the denominator grows faster, the limit is 0 → continue checking decreasing behavior.

Harmonic-type terms

an=1n,1np a_n = \frac{1}{n}, \quad \frac{1}{n^p}

  • Limit = 0
  • Decreasing

So the alternating version converges, even though the regular harmonic series diverges. That contrast shows up a lot on multiple choice.

Logarithmic terms

an=ln⁡(n) a_n = \ln(n)

Limit goes to infinity → diverges immediately.

an=ln⁡(n)n a_n = \frac{\ln(n)}{n}

Limit = 0. Usually decreasing for large nn, so AST often works here.

Trig disguises

Always simplify:

cos⁡(nπ)=(−1)n \cos(n\pi) = (-1)^n

Students sometimes miss this and use the wrong test. The AP loves hiding alternating behavior inside trig.

Conditional vs Absolute Convergence

AST only tells you the series converges. It does not tell you whether it converges absolutely.

If
∑∣an∣ \sum |a_n|
also converges, that’s absolute convergence.

If the alternating series converges but the non-alternating version diverges, that’s conditional convergence.

AST alone does not test absolute convergence.

Key Takeaways

You must check both conditions: lim⁡an=0\lim a_n = 0 and ana_n decreasing.
If lim⁡an≠0\lim a_n \neq 0, the series diverges immediately.
Always analyze ana_n, not the signed term.
cos⁡(nπ)\cos(n\pi) is the same as (−1)n(-1)^n.
AST proves convergence, not absolute convergence.
On written responses, you must justify why ana_n is decreasing, not just claim it.

AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse this website.

Notes

1 credit used · 5/5 remaining