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Reading Time: 6 min
Last Updated: March 30, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: March 30, 2026
Main Ideas: 5

Topic 6.4 Notes – The Fundamental Theorem of Calculus and Accumulation Functions

Verified for 2027 AP® Calculus BC Exam
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You’ll see how an integral with a variable upper bound becomes an accumulation function and why its derivative gives you back the original integrand.

The Fundamental Theorem of Calculus and Accumulation Functions

Take a continuous function f f . Now define a new function:

F(x)=∫axf(t) dt F(x) = \int_a^x f(t)\,dt

This is an accumulation function. For each value of x x , it gives the net signed area under f f from a fixed starting point a a to that x x .

A definite integral usually gives a number.
If one bound is a variable, it gives a function.

Here’s the key result:

ddx(∫axf(t) dt)=f(x) \frac{d}{dx} \left( \int_a^x f(t)\,dt \right) = f(x)

That’s the Fundamental Theorem of Calculus (Part 1).

It says:

  • Integration accumulates change.
  • Differentiation measures instantaneous change.
  • If f f is continuous, these undo each other.

So every accumulation function is automatically an antiderivative of f f .

What this looks like in action

Suppose

F(x)=∫0xet dt F(x) = \int_0^x e^t \, dt

You could evaluate the integral and get ex−1 e^x - 1 .
Or you could use the theorem immediately:

F′(x)=ex F'(x) = e^x

The derivative of the accumulation function is just the integrand with t t replaced by x x .

Notice something important: the t t inside the integral is a dummy variable. It disappears after differentiation.

What an Accumulation Function Represents

Think of f(x) f(x) as a rate.

  • If f f is velocity → F F is position change.
  • If f f is a growth rate → F F is total growth.
  • If f f is flow rate → F F is total volume accumulated.

Here’s the visual idea. The graph shows f(x) f(x) and the shaded region from a fixed starting point to a moving right endpoint x x .

Study guide illustration

Accumulated area under f f from a fixed left endpoint to x x

As x x moves right, the shaded area grows. The rate at which it grows at that instant is f(x) f(x) . That’s exactly what the theorem says: F′(x)=f(x) F'(x) = f(x) .

Connecting behavior of F F and f f

Because F′(x)=f(x) F'(x) = f(x) :

  • If f(x)>0 f(x) > 0 , then F F is increasing.
  • If f(x)<0 f(x) < 0 , then F F is decreasing.
  • Critical points of F F happen where f(x)=0 f(x) = 0 .
  • Since F′′(x)=f′(x) F''(x) = f'(x) , concavity of F F depends on whether f f is increasing or decreasing.

This shows up a lot on FRQs. You’re often given a graph of f f and asked about where F F increases, has extrema, or changes concavity.

Representing Accumulation Functions with Integrals

You should be comfortable writing a function defined by accumulation.

Example:
Let r(t) r(t) be the rate (in liters per minute) at which water flows into a tank.
Then the total water added from time 2 to time x x is

A(x)=∫2xr(t) dt A(x) = \int_2^x r(t)\,dt

That’s exactly what FUN-5 is about. A definite integral can define a new function.

And as long as r r is continuous,

A′(x)=r(x) A'(x) = r(x)

On a multiple-choice question, they may give you a messy integrand. Don’t integrate it unless they ask you to. If the question is asking for the derivative, just apply the theorem.

What Has to Be True

The theorem requires:

  • f f is continuous on an interval containing a a .

On the AP exam, they usually state continuity. If they don’t, assume it unless the problem clearly suggests otherwise.

Common Errors I See Every Year

  • Writing the derivative as f(t) f(t) instead of replacing with x x .
  • Trying to actually compute the integral before differentiating.
  • Forgetting that the result is about rate of accumulation, not total area.
  • Mixing up definite integrals that give numbers with accumulation functions that give functions.

Key Takeaways

An accumulation function has the form F(x)=∫axf(t) dt F(x) = \int_a^x f(t)\,dt and represents net signed area from a a to x x .
If f f is continuous, then F′(x)=f(x) F'(x) = f(x) .
The variable inside the integral is a dummy variable and disappears after differentiation.
If f(x)>0 f(x) > 0 , then the accumulation function is increasing at x x .
You usually do not evaluate the integral when asked for the derivative of an accumulation function.

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Notes

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