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Reading Time: 5 min
Last Updated: February 20, 2026
Main Ideas: 5
Reading Time: 5 min
Last Updated: February 20, 2026
Main Ideas: 5

Topic 2.2 Notes – Defining the Derivative of a Function and Using Derivative Notation

Verified for 2027 AP® Calculus BC Exam
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Derivatives turn average rates of change into instantaneous ones. In this topic, you define the derivative using a limit, connect it to the slope of a tangent line, and get comfortable with derivative notation and representations. This is the foundation everything else in Unit 2 builds on.

1. The Derivative as a Limit

You already know the average rate of change on an interval [x,x+h][x, x+h]:

f(x+h)−f(x)h \frac{f(x+h)-f(x)}{h}

That fraction is called the difference quotient. Geometrically, it’s the slope of a secant line through two points on the graph.

To get the instantaneous rate of change, we shrink the interval:

f′(x)=lim⁡h→0f(x+h)−f(x)h f'(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}

This limit, if it exists, defines the derivative.

Key ideas to lock in:

  • The derivative is a function.
  • f′(x)f'(x) gives the slope of the tangent line at each xx.
  • If the limit does not exist, the function is not differentiable at that point.

Here’s the geometry behind it. The graph below shows a curve (like y=x2y = x^2) with a secant line through two points and the tangent line at one of them.

Secant lines approaching a tangent line as h→0h \to 0

As h→0h \to 0, the secant line becomes the tangent line. That visual connection is the entire reason the limit definition matters.

2. Derivative Notation

If y=f(x)y = f(x), all of these mean the same thing:

  • f′(x)f'(x)
  • y′y'
  • dydx\dfrac{dy}{dx}

They just emphasize different viewpoints:

  • f′(x)f'(x): derivative as a function
  • f′(a)f'(a): a number (the slope at x=ax=a)
  • dydx\dfrac{dy}{dx}: rate language, “change in yy with respect to xx”

On quizzes and the AP exam, notation switches constantly. If a problem says “find dydx\frac{dy}{dx},” it’s not a different task. It’s the derivative.

3. Using the Limit Definition to Find the Derivative

If a problem says “use the definition,” you must start with the limit. No shortcuts.

The Process

  1. Write

    f′(x)=lim⁡h→0f(x+h)−f(x)h f'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h}

  2. Carefully compute f(x+h)f(x+h). This is where most mistakes happen.
  3. Expand completely.
  4. Combine like terms.
  5. Factor out hh from the numerator.
  6. Cancel the hh.
  7. Take the limit by plugging in h=0h=0.

If the hh doesn’t cancel, check your algebra.

Quick Example

Let f(x)=2x2−5xf(x)=2x^2-5x.

  • f(x+h)=2(x+h)2−5(x+h)f(x+h)=2(x+h)^2-5(x+h)
  • Expand:

    2(x2+2xh+h2)−5x−5h 2(x^2+2xh+h^2)-5x-5h

  • Subtract f(x)f(x), simplify:

    4xh+2h2−5h 4xh+2h^2-5h

  • Factor:

    h(4x+2h−5) h(4x+2h-5)

  • Cancel hh, take the limit:

f′(x)=4x−5 f'(x)=4x-5

This process shows up often on no-calculator multiple choice because it tests algebra control.

4. Tangent Lines

The derivative at a point gives the slope of the tangent line:

f′(a)=slope at x=a f'(a)=\text{slope at } x=a

To find the equation of the tangent line at x=ax=a:

  1. Find f′(x)f'(x).
  2. Compute m=f′(a)m=f'(a).
  3. Use point-slope form:

    y−f(a)=m(x−a) y-f(a)=m(x-a)

Example:
If f(x)=x3f(x)=x^3 and you want the tangent line at x=2x=2:

  • f′(x)=3x2f'(x)=3x^2
  • f′(2)=12f'(2)=12
  • Point is (2,8)(2,8)

Tangent line:
y−8=12(x−2) y-8=12(x-2)

On FRQs, missing point-slope form or using the wrong point is a common way students lose easy points.

If the graph has a corner, cusp, vertical tangent, or discontinuity, the derivative does not exist there.

5. Multiple Representations of the Derivative

You need to recognize derivatives in four forms.

Graphical

  • Positive derivative → function increasing
  • Negative derivative → decreasing
  • Zero derivative → horizontal tangent

Numerical

Estimate with small difference quotients:
f(3.01)−f(3)0.01 \frac{f(3.01)-f(3)}{0.01}
Smaller intervals give better approximations.

Analytical

Using the limit definition to produce a formula for f′(x)f'(x).

Verbal

Interpreting meaning in context:

  • “The rate at which water depth is rising at time tt.”
  • “Instantaneous velocity.”

The AP exam loves switching between these without warning. If you truly understand the derivative, the representation doesn’t matter.

Key Takeaways

The derivative is defined by f′(x)=lim⁡h→0f(x+h)−f(x)hf'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h}, and that limit must exist.
The difference quotient represents a secant slope before the limit turns it into a tangent slope.
f′(x)f'(x) is a function, while f′(a)f'(a) is a number.
If the hh does not factor and cancel when using the definition, your algebra is off.
The equation of a tangent line always uses y−f(a)=f′(a)(x−a)y-f(a)=f'(a)(x-a).
Corners, cusps, vertical tangents, and discontinuities mean the function is not differentiable there.

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Notes

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