6m left·0%
Reading Time: 6 min
Last Updated: March 9, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: March 9, 2026
Main Ideas: 5

Topic 6.5 Notes – Interpreting the Behavior of Accumulation Functions Involving Area

Verified for 2027 AP® Calculus BC Exam
Read aloud
Accumulation functions are built from definite integrals with a variable upper bound. In this topic, you use the Fundamental Theorem of Calculus to connect the graph or data for a function ff to the behavior of a new function g(x)=∫axf(t) dtg(x) = \int_a^x f(t)\,dt. Almost every question asks you to analyze gg using information about ff.

1. What an Accumulation Function Is

An accumulation function is defined by

g(x)=∫axf(t) dt g(x) = \int_a^x f(t)\,dt

This means:

  • g(x)g(x) is the net signed area under ff from x=ax=a to x=xx=x.
  • Area above the x-axis counts positive.
  • Area below the x-axis counts negative.

By the Fundamental Theorem of Calculus:

  • g′(x)=f(x)g'(x) = f(x)
  • g′′(x)=f′(x)g''(x) = f'(x)

That connection drives everything in this unit.

If you remember nothing else, remember this:

The graph of ff is the graph of g′g'.

So:

  • If f(x)>0f(x) > 0, then g′(x)>0g'(x) > 0 → g is increasing
  • If f(x)<0f(x) < 0, then g′(x)<0g'(x) < 0 → g is decreasing
  • If f(x)=0f(x) = 0, then g′(x)=0g'(x)=0 → possible critical point of g

Since g′′(x)=f′(x)g''(x) = f'(x):

  • If ff is increasing → gg is concave up
  • If ff is decreasing → gg is concave down

You are always analyzing ff to understand gg.

2. Analyzing g(x)=∫axf(t) dtg(x) = \int_a^x f(t)\,dt from Information About ff

Most problems give you a graph, table, equation, or context for ff and ask about gg.

A. Increasing and Decreasing

Because g′(x)=f(x)g'(x)=f(x):

  • gg increases where ff is above the x-axis.
  • gg decreases where ff is below the x-axis.

For local extrema of gg:

  • Local max when ff changes from positive to negative.
  • Local min when ff changes from negative to positive.

Zeros alone are not enough. You must check the sign change.

B. Concavity and Inflection Points

Because g′′(x)=f′(x)g''(x)=f'(x):

  • gg is concave up where ff is increasing.
  • gg is concave down where ff is decreasing.

Inflection points of gg happen where ff changes from increasing to decreasing or vice versa.

Students often mix this up and look at where f=0f=0. That tells you about extrema of gg, not concavity.

C. Finding Values of g(x)g(x)

To find g(x)g(x), interpret it as signed area.

If you’re given a graph, break it into geometric shapes and compute each piece.

In the graph above, you can see a triangle above the axis, a rectangle below the axis, and a semicircle above the axis. Each contributes positive or negative area to g(x)g(x).

For example:

  • Triangle area =12bh=\frac{1}{2}bh
  • Rectangle area =bh=bh
  • Semicircle area =12πr2=\frac{1}{2}\pi r^2

Add areas above the axis. Subtract areas below.

Be careful with:

  • Reversing bounds (which flips the sign)
  • Forgetting that below-axis area is negative

On FRQs, you must show the geometric work to earn full credit.

3. Working Across Representations

The AP rotates formats constantly. Same idea, different surface.

A. Graph of ff

Most common situation.

In the diagram, you’re given the graph of y=f(x)y=f(x) with shaded regions representing signed area.

Study guide illustration

Graph of y=f(x)y=f(x) with signed area regions

When you see this:

  • Treat it as g′g'.
  • Sign of graph → increasing/decreasing of gg.
  • Slope of graph → concavity of gg.
  • Area → values of gg.

Big trap: students describe the graph as if it were gg. It’s not.

B. Table of Values

If given values of ff:

  • Positive entries → gg increasing there.
  • Negative entries → gg decreasing.
  • Changes in ff help you estimate concavity of gg.
  • Approximate g(b)g(b) using Riemann sums if asked.

You cannot magically know exact values unless integration is possible.

C. Equation for ff

If f(x)f(x) is given explicitly:

  • Solve f(x)>0f(x)>0 for increasing.
  • Compute f′(x)f'(x) for concavity.
  • Evaluate definite integrals directly for g(x)g(x).

On no-calculator sections, expect manageable algebra.

D. Verbal Context

If ff is a rate (gallons/hour, people/minute, meters/second):

  • gg is the total accumulated amount.
  • Units of gg = (units of ff) × (units of xx).

Example: velocity in meters/second → accumulation gives total displacement in meters.

4. Absolute Extrema of an Accumulation Function

On a closed interval:

  1. Find critical points where f(x)=0f(x)=0.
  2. Evaluate gg at:
    • Endpoints
    • Those critical points
  3. Compare values.

Do not assume the highest point of ff gives the max of gg. Accumulation depends on total area, not height.

5. Common Mistakes

  • Mixing up ff, gg, g′g', and g′′g''.
  • Forgetting endpoints for absolute extrema.
  • Calling every zero of ff a max or min of gg.
  • Using sign of ff to determine concavity of gg.
  • Dropping a negative when area is below the axis.

Key Takeaways

If g(x)=∫axf(t) dtg(x)=\int_a^x f(t)\,dt, then g′(x)=f(x)g'(x)=f(x) and g′′(x)=f′(x)g''(x)=f'(x).
Increasing/decreasing of gg comes from the sign of ff, not the slope of ff.
Concavity of gg comes from whether ff is increasing or decreasing.
Zeros of ff are critical points of gg, but only sign changes create extrema.
Accumulation means signed area, so below-axis regions subtract.
For absolute extrema of gg, always test endpoints and where f(x)=0f(x)=0.

AP® is a trademark registered by the College Board, which is not affiliated with, and does not endorse this website.

Notes

1 credit used · 5/5 remaining