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Reading Time: 6 min
Last Updated: March 5, 2026
Main Ideas: 5
Reading Time: 6 min
Last Updated: March 5, 2026
Main Ideas: 5

Topic 5.8 Notes – Sketching Graphs of Functions and Their Derivatives

Verified for 2027 AP® Calculus BC Exam
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You connect f f , f′ f' , and f′′ f'' across graphs, tables, and formulas. The goal isn’t just drawing curves - it’s justifying exactly why a function increases, decreases, curves up, or curves down.

How derivatives determine the shape of a graph

Everything starts with what the derivatives mean.

First derivative f′(x) f'(x) → slope behavior

  • f′(x)>0 f'(x) > 0 → f f is increasing
  • f′(x)<0 f'(x) < 0 → f f is decreasing
  • f′(x)=0 f'(x) = 0 or undefined → critical point

Critical points are candidates for local maxima or minima. They are not automatically extrema.

Second derivative f′′(x) f''(x) → concavity

  • f′′(x)>0 f''(x) > 0 → concave up (slopes increasing)
  • f′′(x)<0 f''(x) < 0 → concave down (slopes decreasing)
  • Sign change in f′′ f'' → possible inflection point

Here’s a single graph that ties these ideas together. Notice how the sign of f′ f' matches increasing or decreasing behavior, and how points where f′=0 f' = 0 or is undefined show up as critical points.

Study guide illustration

Graph showing critical points and intervals of increase and decrease

If you can look at a graph like this and mentally describe where f′ f' is positive or negative and where f′′ f'' changes sign, you understand this topic.

The full graph sketching process

When you’re given an equation and asked to sketch f f , build the structure piece by piece.

1. Domain and discontinuities

  • Polynomials → domain is all real numbers.
  • Rational/log functions → check where undefined.
  • Note vertical asymptotes or holes if they exist.

2. Intercepts and symmetry

  • x‑intercepts → solve f(x)=0 f(x)=0
  • y‑intercept → compute f(0) f(0)
  • Even → f(−x)=f(x) f(-x)=f(x)
  • Odd → f(−x)=−f(x) f(-x)=-f(x)

These anchor your sketch.

3. Critical points

Solve f′(x)=0 f'(x)=0 (or where undefined but in domain).

These split the number line into intervals for sign analysis.

4. Increasing and decreasing intervals

Test values in each interval:

  • f′>0 f'>0 → increasing
  • f′<0 f'<0 → decreasing

If the sign changes:

  • +→− + \to - → local max
  • −→+ - \to + → local min

You must reference the sign change when justifying on FRQs.

5. Concavity and inflection points

Solve f′′(x)=0 f''(x)=0 for candidates.
Check sign change of f′′ f'' .

No sign change means no inflection point. This is a very common mistake.

Moving between f f , f′ f' , and f′′ f''

A lot of AP questions give you only a graph of f′ f' or a table of values of f′′ f'' and ask about f f . You need to translate quickly.

Here’s the relationship summary:

If you’re given…You can conclude about f
Graph of f′ f' Above x-axis → f increasing
Below x-axis → f decreasing
Sign change → local extremum
Graph of f′′ f'' Positive → concave up
Negative → concave down
Sign change → inflection point
Graph of f f Horizontal tangent → f′=0 f'=0
Steeper slope → larger |f′ f' |
Bending upward → f′′>0 f''>0

One key connection students miss:

If f′ f' has a local max or min, then f′′=0 f''=0 there.
Extrema of f′ f' correspond to zeros of f′′ f'' .

Using numerical and graphical information

Sometimes you’ll get a table:

x123
f′(x) f'(x) -204

From just this:

  • f′ f' changes from negative to positive at x=2 x=2
  • So f f has a local minimum at 2

Even without an equation.

If you’re given a graph of f′ f' that touches but doesn’t cross the axis, that means:

  • f′(c)=0 f'(c)=0
  • No sign change
  • No local extremum

The AP loves that subtlety.

Justifying correctly

Strong explanations sound like this:

  • “Since f′(x)>0 f'(x) > 0 for 1<x<4 1<x<4 , f f is increasing on (1,4) (1,4) .”
  • “Because f′ f' changes from positive to negative at x=3 x=3 , f f has a local maximum at 3.”
  • “Since f′′(x)<0 f''(x) < 0 , the graph is concave down.”

Always reference the derivative, the sign, and the interval or point.

Key Takeaways

A critical point requires f′(c)=0 f'(c)=0 or undefined, but an extremum requires a sign change in f′ f' .
An inflection point requires a sign change in f′′ f'' , not just f′′(c)=0 f''(c)=0 .
Increasing/decreasing comes from f′ f' ; concavity comes from f′′ f'' .
Zeros of f′ f' match horizontal tangents of f f .
Local extrema of f′ f' occur where f′′=0 f''=0 .
If f′ f' only touches the axis and does not cross, f f has no local extremum there.

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Notes

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